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Mkey [24]
3 years ago
9

Magnesium has 2 valence electrons, and oxygen has 6 valence electrons. which type of bonding is likely to occur between a magnes

ium atom and an oxygen atom?ionic—magnesium will give 2 electrons to oxygen, and both will become ions.ionic—oxygen will give 2 electrons to magnesium, and both will become ions.metallic—oxygen and magnesium atoms will be surrounded by a pool of electrons.
Chemistry
1 answer:
choli [55]3 years ago
5 0
The bond formed between them will be ionic and Mg will give 2 electrons to oxygen.
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The table below lists the properties of a metallic element. Shiny, Silver colored, Forms +1 and +2 ions, compound with sulfur is
shtirl [24]

Answer:

The correct option is;

Group 12

Explanation:

A metallic element that is shiny and silver colored that can exist in the +1 and +2 ionic states and  which forms a bright red compound with sulfur is mercury, Hg

The compound formed between mercury and silver is one of the earliest synthetic compound also known as vermilion and cinnabar. The bright red pigment of the HgS is used widely and is one of the most favorite pigment found in medieval European outstanding works of arts and in Chinese decorated wares made of lacquer as well as in mesoAmerica.

5 0
3 years ago
Read 2 more answers
Balancing H2SO4+NH4OH —> H2O+(NH4)2SO4
azamat

H₂SO₄   +    2NH₄OH    →     (NH₄)₂SO₄   +    2H₂O

Explanation:

  Unbalanced reaction equation:

                    H₂SO₄   +    NH₄OH    →     (NH₄)₂SO₄   +    H₂O

We can use a simple mathematical approach to balance this equation by solving simple algebraic equations.

         aH₂SO₄   +    bNH₄OH    →     c(NH₄)₂SO₄   +    dH₂O

a,b,c and d are simple coefficients that will balance the equation:

   Conservation of H: 2a + 5b = 8c + 2d

                               S:   a = c

                               O:  4a + b = 4c + d

                               N:   b = 2c

lets assume that a = 1

                             c= 1

                             b = 2

                  Solving for d from 4a + b = 4c + d

                   d = 4a + b -4c = 4(1) + 2 - 4(1) = 2        

 

                  H₂SO₄   +    2NH₄OH    →     (NH₄)₂SO₄   +    2H₂O

Learn more:

Balancing of equations brainly.com/question/6078553

#learnwithBrainly

3 0
4 years ago
X2o3 express you answer as a whole number
kobusy [5.1K]
 <span>2.40 - 1.68 =0.72 g of oxigen 
moles = 0.72/16 g/mol=0.045 

moles x = 1.68/ 55.9=0.03 

0.03/0.03 = 1 = x 
0.045 / 0.03 = 1.5 = O 

to get whole numbers multiply by 2 

x2O3 

X2O3 +3 CO = 2 X + 3 CO2</span>
4 0
4 years ago
What is the charge of a proton, electron and neutron
Elza [17]

Answer:

  • a proton has a<u> positive</u> charge
  • an electron has a<u> negative</u> charge
  • a neutron has a <u>neutral </u>charge

#answerwithquality #BAL

4 0
4 years ago
Read 2 more answers
If a buffer has an initial pH of 6.34 and the acid has a Ka of 3.46 × 10-4, what is the ratio of conjugate base to weak acid in
Sloan [31]

Answer: The ratio of conjugate base to weak acid in the buffer system is 758 : 1

Explanation:

The dissociation constant for  acid = K_a=3.46\times 10^{-4}

pH = 6.34

First we have to calculate the value of pK_a.

The expression used for the calculation of pK_a is,

pK_a=-\log (K_a)

Now put the value of K_a in this expression, we get:

pK_a=-\log (3.46\times 10^{-4})

pK_a=3.46

Now we have to calculate the ratio of conjugate base to weak acid in the buffer system

Using Henderson Hesselbach equation :

pH=pK_a+\log \frac{[\text {conjugate base}]}{[Acid]}

Now put all the given values in this expression, we get:

6.34=3.46+\log \frac{[\text {conjugate base}]}{[Acid]}

\frac{[\text {conjugate base}]}{[Acid]}=758

Therefore, the ratio of conjugate base to weak acid in the buffer system is 758: 1

3 0
4 years ago
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