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dlinn [17]
3 years ago
12

A cube of metal has a mass of 5.05 x 10°g and its density is known to be 12.77 g/mL, what is the volume of this metal?

Chemistry
1 answer:
Usimov [2.4K]3 years ago
8 0

Answer:

Explanation:

option A is correct

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Write down all the food chains that start with the blackberry and end with the hawk.
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Blackberry - rabbit - snake - owl - hawk<span>
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3 years ago
What happens to the kinetic energy of a ball if its velocity is increased to twice its original value?
dem82 [27]

Answer:

idk

Explanation:

4 0
3 years ago
Roxanne was asked by her teacher to explain why sodium ions (Na) and chlorine ions (CI) combine into sodium chloride (NaCl).
DedPeter [7]

Answer:

Roxanne said it was because chlorine is highly electronegative and sodium has a low ionization energy and that the ions Na and cr both have full electron shells.

3 0
3 years ago
A voltaic cell is made using a lead electrode and copper electrode. The electrolytes for each half cell are lead nitrate and cop
lisov135 [29]

The cell notation is Pb_{(s)}  Pb^{2+} _{(aq)} ║Cu^{+2}_{aq}  Cu_{(s)} and the cell potential is 0.464

The reaction occurred while losing of hydron is known as oxidation reaction

We can also tell that the reaction occurred while gaining of oxygen atom is known as oxidation reaction.

The reaction occurred while gaining of hydrogen is known as reduction reaction or we can say that the reaction occurred while losing oxygen atom is known as reduction reaction

An electrochemical cell's cell potential is defined as the difference in potential between two half cells. The electrons' capacity to go from one half cell to the other is what causes the potential difference. As a result of the chemical reaction being a redox reaction, electrons can travel across electrodes.

Calculating the Cell potential

E°cell  = E°(reduction) - E°(oxidation)

           = 0.34 - (-0.0124)

           = 0.464

Hence the cell potential is 0.464

Learn more about Cell potential here

brainly.com/question/11638563

#SPJ10

6 0
1 year ago
Calculate the average atomic mass of an element containing 39.9% of atoms with a mass of 69 amu and 60.1% of atoms with a mass o
emmainna [20.7K]

Answer:

70.202 amu

Explanation:

From the question given above, the following data were obtained:

Isotope A:

Abundance (A%) = 39.9%

Mass of A = 69 amu

Isotope B:

Abundance (B%) = 60.1%

Mass of B = 71 amu

Average atomic mass =?

The average atomic mass of the element can be obtained as follow:

Average atomic mass = [(Mass of A × A%)/100] + (Mass of B × B%)/100]

= [(69 × 39.9)/100] + [(71 × 60.1)/100]

= 27.531 + 42.671

= 70.202 amu

Therefore, the average atomic mass of the element is 70.202 amu

4 0
3 years ago
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