The equivalent expression for [gofoh](9) is 5(32(9)^5-1).
According to the given question.
We have three functions
f(x) = x^5 - 1
g(x) = 5x^2
h(x) = 2x
Here, we have to find the equivalent expression for [gofoh](9).
so,
gofoh(x)
= g((2x)^5 -1)
= g(32x^5 -1)
= 5(32x^5 -1)
Therefore,
gofoh(9)
= 5(32(9)^5-1)
Hence, the equivalent expression for [gofoh](9) is 5(32(9)^5-1).
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Answer:
No, Tina is not correct since 3.4 × 105 = 357 and 8.25 × 104 = 858
diameter (d) = 2 · r
Circumference (C) = 2 π · r → C = π · d → d =
Answer:
x = 14
Step-by-step explanation:
5x - 40 = 30
+40 +40
5x = 70
divide by 5 on both sides
x= 14
Answer:
y = -4x² + 32x - 48
Step-by-step explanation:
The standard form of a quadratic equation is
y = ax² + bx + c
We must find the equation that passes through the points:
(2, 0), (6,0), and (3, 12)
We can substitute these values and get three equations in three unknowns.
0 = a(2²) + b(2) + c
0 = a(6²) + b(6) + c
12 = a(3²) + b(3) + c
We can simplify these to get the system of equations:
(1) 0 = 4a + 2b + c
(2) 0 = 36a + 6b + c
(3) 12 = 9a + 3b + c
Eliminate c from equations (1) and (2). Subtract (1) from (2).
(4) 0 = 32a + 4b
Eliminate c from equations (2) and (3). Subtract (3) from (2).
(5) -12 = 27a - 3b
Simplify equations (4) and (5).
(6) 0 = 8a + b
(7) -4 = 9a - b
Eliminate b by adding equations (6) and (7).
(8) a = -4
Substitute (4) into (6).
0 = -32 + b
(9) b = 32
Substitute a and b into (1)
0 = 4(-4) + 2(32) + c
0 = -16 + 64 + c
0 = 48 + c
c = -48
The coefficients are
a= -4, b = 32, c = -48
The quadratic equation is
y = -4x² + 32x - 48
The diagram below shows the graph of your quadratic equation and the three points through which it passes.