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REY [17]
3 years ago
14

According to the law of reflection, the angle of incidence is equal to the angle of

Physics
2 answers:
KonstantinChe [14]3 years ago
5 0
Angle Of incidence is equal to angle of reflection.

Darina [25.2K]3 years ago
3 0

Before going to answer this question first we have to understand reflection and laws of reflection.

Reflection is the optical phenomenon in which light will bounce back to the same medium from which it had originated .

Whenever a light ray will incident on a mirror or any reflecting surface, it will be reflected. The ray which falls on the reflecting surface is called incident ray and the ray which is reflected is called reflected ray.

Let us consider a normal to the point of incidence.The angle made by incident ray with the normal is called angle of incidence.Let it be denoted as[ i ]

The angle made by the reflected ray with the normal is called angle of incidence.Let it be denoted as [r]

There are two types of reflection.One is called regular and other one is called as irregular.The laws of reflection is valid for both the types of reflection.

There are two laws of reflection.

FIRST LAW -It states that the incident ray,reflected ray and the normal to the point of incidence,all lie in one plane.

SECOND LAW- It states that that the angle of incidence is equal to the angle of reflection irrespective of the type of reflection.i.e i =r

Hence the correct answer will be angle of reflection.

                                         

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Answer:

1.697s

Explanation:

We use the second equation of free fall under gravity as follows;

h=ut+\frac{1}{2}gt^2...............(1)

Since  the ball fell freely, u = 0m/s, therefore equation (1) reduces to

h=\frac{1}{2}gt^2...............(2)

Given that h is the total height the ball falls through in time t seconds.

However, according to the stated problem the ball falls halfway in 1.2s, this simply implies that the ball falls through a distance of \frac{h}{2} in 1.2s. Hence we can write the following, given that g=9.8m/s^2;

\frac{h}{2}=\frac{1}{2}*9.8*1.2^2\\hence\\h=9.8*1.2^2\\h=14.112m

We can now proceed to find the time t for which it falls through h = 14.112m as follows;

14.112=\frac{1}{2}*9.8*t^2\\14.112=4.9t^2\\t^2=\frac{14.112}{4.9}\\t^2=2.88\\t=\sqrt{2.88} \\t=1.697s

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