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3 years ago

11

How can you decrease the amount of input force of a wheel and axle?

1 answer:

nasty-shy [4]3 years ago

7 0

Explanation:

hmm by the increasing the size of wheel and decreasing axle

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What determines the color of light?

crimeas [40]

Answer: wave length
(Please Mark brainly or like I’m trying to get points lol!)

3 0

3 years ago

Coal is how much worse than natural gas when it comes to carbon dioxide emissions?

Naya [18.7K]

Answer:

True

Explanation:

Its worse

4 0

3 years ago

An engineer examining the oxidation of SO 2 in the manufacture of sulfuric acid determines that Kc = 1.7 x 108 at 600 K:

kozerog [31]

Answer: $p_{SO_2}=0.017atm$

Explanation:

We are given:

$K_c=1.7\times 10^8$

Relation of $K_p$ with $K_c$ is given by the formula:

$K_p=K_c(RT)^{\Delta ng}$

Where,

$K_p$ = equilibrium constant in terms of partial pressure = ?

$K_c$ = equilibrium constant in terms of concentration

R = Gas constant = $0.0821\text{ L atm }mol^{-1}K^{-1}$

T = temperature = $600K$

$2SO_2(g)+O_2(g)\rightleftharpoons 2SO_3(g)$

$\Delta ng$ = change in number of moles of gas particles = $n_{products}-n_{reactants}=2-3=-1$

Putting values in above equation, we get:

$K_p=1.7\times 10^8\times (0.0821\times 600)^{-1}\\\\K_p=3.4\times 10^6$

The chemical reaction follows the equation:

$2SO_2(g)+O_2(g)\rightleftharpoons 2SO_3(g)$

The expression for $K_p$ for the given reaction follows:

$K_p=\frac{(p_{SO_3})^2}{ p_{O_2}\times {(p_{SO_2})^2}}$

We are given:

$p_{SO_3}=300atm$ $p_{O_2}=100atm$

Putting values in above equation, we get:

$3.4\times 10^6=\frac{(300)^2}{100\times {(p_{SO_2})^2}}$

$p_{SO_2}=0.017atm$

Hence, the partial pressure of the $SO_2$ at equilibrium is 0.017 atm.

3 0

3 years ago

In a scientific investigation of lakes the depth pf a lake is most likely to be measured in

sasho [114]

It is meters for most lakes hope this helps.

3 0

3 years ago

Anjali's plane had been flying through calm skies (no wind) with a velocity (speed and direction) vector <img src="https://tex.z

grin007 [14]

Answer:

The speed of the wind is 70.7 units.

Explanation:

The velocity of the wind is equal to plane's velocity before the wind minus its velocity after the wind:

$\vec{v_{w}}=\vec{v_1}-\vec{v_2}= (400,100)- (350,50)$

$\boxed{\vec{v_{w}} = (50,50)}$

Now, the speed of the wind is the magnitude of $\vec{v_{w}}$ :

$|\vec{v_{w}}| = \sqrt{50^2+50^2}$

$\boxed{|\vec{v_{w}}| = 70.7}$

which is the speed of the wind.

<em>P.S: No units are given for speed because no units were provided in the question.</em>

5 0

4 years ago