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2 years ago

5

Which of the following is a true statement about magnetic fields

1 answer:

zaharov [31]2 years ago

8 0

a. the larger the current, the larger the magnetic field

Explanation:

The magnetic field produced by a current-carrying wire is given by the equation:

$B=\frac{\mu_0 I}{2\pi r}$

where

$\mu_0$ is the vacuum permeability

I is the current in the wire

r is the distance from the wire at which the field strength is calculated

From the equation, we notice the following points:

The strength of the magnetic field is directly proportional to the current in the wire
The strength of the magnetic field is inversely proportional to the distance from the wire

Therefore, the only correct option in the list is

a. the larger the current, the larger the magnetic field

Learn more about magnetic fields:

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3 years ago

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3 years ago

Read 2 more answers

Suppose you could fit 100 dimes, end to end, between your card with the pinhole and your dime-sized sunball. how many suns could

Naddika [18.5K]

Answer: 100 suns

Explanation:

We can solve this with the following relation:

$\frac{d}{x_{sunball-pinhole}}=\frac{D}{x_{sun-pinhole}}$

Where:

$d=17.91 mm =17.91(10)^{-3} m$ is the diameter of a dime

$D$ is the diameter of the Sun

$x_{sun-pinhole}=150,000,000 km=1.5(10)^{11} m$ is the distance between the Sun and the pinhole

$x_{sunball-pinhole}=100 d=1.791 m$ is the amount of dimes that fit in a distance between the sunball and the pinhole

Finding $D$ :

$D=\frac{d}{x_{sunball-pinhole}}x_{sun-pinhole}$

$D=\frac{17.91(10)^{-3} m}{1.791 m} 1.5(10)^{11} m$

$D=1.5(10)^{9} m$ This is roughly the diameter of the Sun

Now, the distance between the Earth and the Sun is one astronomical unit (1 AU), which is equal to:

$1 AU=149,597,870,700 m$

So, we have to divide this distance between $D$ in order to find how many suns could it fit in this distance:

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3 years ago