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OLEGan [10]
3 years ago
5

Which of the following is a true statement about magnetic fields

Physics
1 answer:
zaharov [31]3 years ago
8 0

a. the larger the current, the larger the magnetic field

Explanation:

The magnetic field produced by a current-carrying wire is given by the equation:

B=\frac{\mu_0 I}{2\pi r}

where

\mu_0 is the vacuum permeability

I is the current in the wire

r is the distance from the wire at which the field strength is calculated

From the equation, we notice the following points:

  • The strength of the magnetic field is directly proportional to the current in the wire
  • The strength of the magnetic field is inversely proportional to the distance from the wire

Therefore, the only correct option in the list is

a. the larger the current, the larger the magnetic field

Learn more about magnetic fields:

brainly.com/question/3874443

brainly.com/question/4240735

#LearnwithBrainly

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Two dump trucks each have a mass of 1,500 kg. The distance of the dump truck
xxTIMURxx [149]

Answer:

6.00 x 10⁻⁸N

Explanation:

Given parameters:

Mass of each dump trucks  = 1500kg

Distance between them  = 50m

Unknown:

New gravitational force between them = ?

Solution:

From Newton's law of universal gravitation,

        F = \frac{G m1 m2}{r^{2} }  

F is the gravitational force

G is the universal gravitation constant

m is the mass

r is the distance

           F  = \frac{6.67 x 10^{-11} x 1500  x 1500}{50^{2} }    = 6.00 x 10⁻⁸N

4 0
2 years ago
Question 1 of 10
Bad White [126]
The answer is b maybe?
3 0
3 years ago
Can anyone help me with this??? Anyone familiar with this sorta project??
SIZIF [17.4K]

yah set up an experiment do u have the rocks with u?


7 0
2 years ago
Rick shoots a basketball at an angle of 35' from the horizontal. It leaves his hands 7 feet from the ground with a velocity of 2
Korvikt [17]

Given:

The angle of projection of the basketball, θ=35°

The height at which the ball leaves the hand, h=7 ft

The initial velocity of the basketball, v=20 ft/s

To find:

The parametric equations describing the shot.

Explanation:

The range, x of the basketball is given by,

x=v\cos\theta t

On substituting the known values,

\begin{gathered} x=20\times\cos35\degree\times t \\ \implies x=16.4t \end{gathered}

The change in the height, y of the basketball is given by,

y=-v\sin\theta t+\frac{1}{2}gt^2

Where g is the acceleration due to gravity.

On substituting the known values,

\begin{gathered} y=-20\times\sin35\degree\times t+\frac{1}{2}\times32\times t^2 \\ \implies y=-11.5t+16t^2 \end{gathered}

Final answer:

The parametric equations describing the shot are

\begin{gathered} \begin{equation*} x=16.4t \end{equation*} \\ \begin{equation*} y=-11.5t+16t^2 \end{equation*} \end{gathered}

8 0
1 year ago
Use the exact values you enter to make later calculations. You repeat the same experiment that you did in the lab with the force
frutty [35]

Answer:

sorry I don't know but I hope you get a answer soon

7 0
3 years ago
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