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posledela
3 years ago
15

A container is filled with a mixture of gases:

Chemistry
1 answer:
strojnjashka [21]3 years ago
8 0

Answer:

The partial pressure of chlorine gas in the mixture is 1.55 atm.

Explanation:

Partial pressure of oxygen gas = p_1=1.0 atm

Partial pressure of nitrogen gas = p_2=0.75 atm

Partial pressure of chlorine gas = p_3=?

Total pressure of the mixture of gases = P = 3.30 atm

Using Dalton's law of partial pressure:

P=p_1+p_2+p_3

3.30 atm=1.0 atm+ 0.75 atm+p_3

p_3=3.30atm - (1.0 atm+ 0.75 atm)=1.55 atm

The partial pressure of chlorine gas in the mixture is 1.55 atm.

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Answer: The pressure in the can is 4.0 atm

Explanation:

According to ideal gas equation:

PV=nRT

P = pressure of gas = ?

V = Volume of gas = 0.410 L

n = number of moles = \frac{\text {given mass}}{\text {Molar mass}}=\frac{3.0g}{44.1g/mol}=0.068mol

R = gas constant =0.0821Latm/Kmol

T =temperature =20^0C=(20+273)K=293K

P=\frac{nRT}{V}

P=\frac0.068mol\times 0.0820 L atm/K mol\times 293K}{0.410L}=4.0atm

Thus the pressure in the can is 4.0 atm

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2 years ago
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Answer:

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Explanation:

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How many moles of ethanol are produced starting with 500.g glucose?
Monica [59]
<h3>Answer:</h3>

5.55 mol C₂H₅OH

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Tables
  • Moles

<u>Stoichiometry</u>

  • Using Dimensional Analysis
  • Analyzing Reactions RxN
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced] C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

[Given] 500. g C₆H₁₂O₆ (Glucose)

[Solve] moles C₂H₅OH (Ethanol)

<u>Step 2: Identify Conversions</u>

[RxN] 1 mol C₆H₁₂O₆ → 2 mol C₂H₅OH

[PT] Molar mass of C - 12.01 g/mol

[PT] Molar Mass of H - 1.01 g/mol

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of C₆H₁₂O₆ - 6(12.01) + 12(1.01) + 6(16.00) = 180.18 g/mol

<u>Step 3: Stoichiometry</u>

  1. [DA] Set up conversion:                                                                                 \displaystyle 500 \ g \ C_6H_{12}O_6(\frac{1 \ mol \ C_6H_{12}O_6}{180.18 \ g \ C_6H_{12}O_6})(\frac{2 \ mol \ C_2H_5OH}{1 \ mol \ C_6H_{12}O_6})
  2. [DA} Multiply/Divide [Cancel out units]:                                                         \displaystyle 5.55001 \ mol \ C_2H_5OH

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

5.55001 mol C₂H₅OH ≈ 5.55 mol C₂H₅OH

8 0
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Lead (ll) nitride+ammonium sulfate &gt; lead(ll) sulfate + ammonium nitride
Alenkinab [10]

Answer:

Pb_3N_2 + 3 (NH_4)_2SO_4\rightarrow 3 PbSO_4 + 2 (NH_4)_3N

Explanation:

Let's rewrite the given word equation in its chemical balanced equation representation:

1. Lead(II) nitride is represented by lead, Pb, in an oxidation state of 2+, while nitride is a typical nitrogen anion with a state 3-. As a result, the lowest common multiple between 2 and 3 is 6, meaning 2 lead cations are needed to balance 3 nitrogen anions: Pb_3N_2.

2. Ammonium sulfate consists of an ammonium cation with a 1+ charge and sulfate anion with a 2- charge, two ammonium cations needed: (NH_4)_2SO_4.

3. Lead(II) sulfate would have one lead cation and one sulfate anion, as they have the same magnitude of charges with opposite signs: PbSO_4.

4. Ammonium nitride would require three amonium cations to balance the nitride anion: (NH_4)_3N.

Let's write the balanced equation:

Pb_3N_2 + 3 (NH_4)_2SO_4\rightarrow 3 PbSO_4 + 2 (NH_4)_3N

7 0
3 years ago
What is the major divide or ridgeline that separate Virginia's watersheds?
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In Virginia, the continental divide separates the New River from the Roanoake and James River. East of the continental divide, the rivers flow east or south toward the Atlantic Ocean. West of the continental divide, the rivers flow north or west toward the Gulf of Mexico by way of the Ohio and the Mississippi Rivers.
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3 years ago
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