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romanna [79]
3 years ago
8

28.5g of iron shot is added to a graduate cylinder containing 45.50 mL of water. The water level rises to the 49.10 mL , From th

is information calculate the density of the iron?
Chemistry
1 answer:
Oxana [17]3 years ago
6 0
To calculate the density of an object you use the density formula which is:

D=m/v

now we plug in what we're given.

m=25.0g
v=49.10mL-45.50mL=3.6mL

D=25.0g/3.6mL=6.9 g/mL

The density of the iron is 6.9 g/mL. (btw, I left the answer in significant figures)


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A mixture of three gases has a total pressure of 365 mmHg. Gas A contributes a pressure of 53 mmHg and gas B contributes a press
adoni [48]
This one is the easiest law, but you would take 53 and 185 and add them together to get 235 and then you will minus 235 and 365 and the answer you are looking for is 130 mmHg! Hopefully this helped you!!

5 0
2 years ago
Estimate the Calorie content of 65 g of candy from the following measurements. A 15-g sample of the candy is placed in a small a
GrogVix [38]

Answer:

The calorie content of  65g of candy is 326.78 cal

Explanation:

Step 1: Data given

Mass of the candy = 15.00 grams

Mass of the container = 0.325 kg

Mass of water = 1.75kg

0.624 kg at an initial temperature of 15.0°C.

The specific heat of aluminium = 0.22 Cal/kg°C

The specific heat of water = 1 cal/kg°C

Step 2: Calculate calorie content for a 15 gram sample

ΔQ = Σm*c*ΔT

 ⇒ m = mass in grams

⇒ with c= the specific heat in Cal/kg°C

⇒ with ΔT = T2 -T1 = the change in temperatures in °C

ΔQ = m(bomb) * C(aluminium) * ΔT + m(cup) * C(aluminium) * ΔT + m(H2O) * c(H20) * ΔT

ΔQ = (m(bomb) + m(cup)) * c(aluminium)  + m(H2O)*c(H20) ) * ΔT

⇒ with mass of the bomb calorimeter = 0.325 kg

⇒ with mass of the cup = 0.624 kg

⇒ with c(aluminium) = the specific heat of aluminium = 0.22 Cal/kg°C

⇒ with mass of water = 1.75 kg

⇒ with c(water) = the heat capacity of water = 1 Cal/kg°C

⇒ with ΔT = the change in temperature = T2 - T1 = 53.5 - 15.0 = 38.5 °C

ΔQ = 0.325*0.22*38.5 + 0.624*0.22*38.5 + 1.75*1*38.5

ΔQ = ((0.325 + 0.624)*0.22 + 1.75*1)*38.5

ΔQ = 75.41 cal

Step 3: Calculate the calorie content for a 65 gram sample

For a 65g sample the calorie content will be more or less 4x higher than a 15 gram sample:

ΔQ = 75.41  * (65/15) = 326.78 cal

8 0
2 years ago
Which of the following is true about chemical bonds?
Sauron [17]
I really don’t know. Sorry
7 0
3 years ago
Read 2 more answers
During chemical weathering, forsterite is dissolved by the carbonic acid in rainwater. The weathering reaction is as follows:
Semenov [28]

Answer:

Keqq = 310

Note: Some parts of the question were missing. The missing values are used in the explanation below.

Explanation:

<em>Given values: ΔH° = -178.8 kJ/mol = -178800 J/mol; T = 25°C = 298.15 K; ΔS° = -552 J/mol.K; R = 8.3145 J/mol.K</em>

Using the formula ΔG° = -RT㏑Keq

㏑Keq = ΔG°/(-RT)

where ΔG° = ΔH° - TΔS°

㏑Keq = ΔH° - TΔS°/(-RT)

㏑Keq = {-178800 - (-552 * 298.15)} / -(8.3145 * 298.15)

㏑Keq = -14221.2/-2478.968175

㏑Keq = 5.73674166

Keq = e⁵°⁷³⁶⁷⁴¹⁶⁶

Keq = 310.05

4 0
3 years ago
What happens to electrons in an ionic bond?
ElenaW [278]

Answer:

the metal loses electrons to become a positively charged cation

Explanation:

4 0
2 years ago
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