You'd use the temperature change equation. The specific heat of water is always 4.18J/(g °C).
Equation to use: q=mCΔT
21.8=(2.0)(4.18)(Tf-5)
21.8=(8.36)(Tf-5)
21.8/8.36=Tf-5
2.61=Tf-5
2.61+5=Tf
Tf=7.61 °C
Since you want to know how many °C it raises, you wouldn't pay attention to the last 2 steps, however if you need to know the final temp, you want to go to the last step.
With standard pressure there is a set list of values. (at STP), most common is 760torr. So whenever you see "at STP" or "at standard temperature pressure" you will use 760torr for pressure. Same thing goes with temperature, if you're not given temp and it says at STP you will use 273K.
For this problem:
You will be using the combined gas law:
(Pressure 1) x (Volume 1) / (Temp. 1) = (Pressure 2) x (Volume 2) / (Temp. 2)
(760torr) x (5.63L) / (287K) = (?) (9.21L) / (287K)
Pressure 2 = 465torr
*Hope this clarifies STP for you! :)
An increase in temperature at constant volume will increase the kinetic energy and the distance. Thus, option c is correct.
<h3>What is Gay-Lussac's law?</h3>
Gay-Lussac's law is the ideal gas law that defines the direct relation of the temperature to the pressure of the gas at a constant volume.
With an increase in the temperature of the gas, the pressure also rises causing the distance between the particle to expand by the increase in the kinetic energy.
Therefore, option c. the kinetic energy, particle distance, and the pressure increases with tempearture rise.
Learn more about Gay-Lussac's law here:
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Answer:
The answer to your question is the third option, atoms of each lose one electron to achieve stability.
Explanation:
a) The first option is incorrect, those elements are extremely reactive and can explode.
b) The option is also incorrect, metalloids are located in groups 3A, 4A OR 5A in the periodic table.
c) This option is correct
d) These elements have 1 valence electron, this option is wrong.
Answer: No the tools are not physically connected to technology to the point they would be rendered unusable like a wrench in a computer or gear box
Explanation: