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3 years ago

15

Which of these is a result of gravitational lensing?

1 answer:

valentina_108 [34]3 years ago

7 0

Answer:

Answer is the formation of multiple images of the same object .

Explanation:

I hope it's helpful!

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Rocks that are formed as a result of deposits from weathering and erosion

zimovet [89]

<h2>Answer: Sedimentary rocks </h2>

Sedimentary rocks are formed from sediments and deposits of particles of various types, forms and sizes that are transported by air, wind or water, and then subjected to chemical processes to become rocks.

These types of rocks are usually found in the form of layers or strata in places where sediment accumulates due to the erosion of other materials, for example on the banks of rivers, in valleys, lakes (and any other type of body of water).

8 0

3 years ago

A car accelerates uniformly from rest to 20 m/sec in 5.6 sec along a level stretch of road. Ignoring friction, determine the ave

bonufazy [111]

Answer:

(a) $P=33000W$

(b) $P=51000W$

Explanation:

The average power is defined as the amount of work done during a time interval:

$P=\frac{W}{t}(1)$

According to work-energy theorem, the work done is equal to the change in kinetic energy. So, we have:

$W=\Delta K\\W=K_f-K_0\\W=\frac{mv_f^2}{2}-\frac{mv_0^2}{2}\\(2)$

Recall that the weight is given by:

$w=mg\\m=\frac{w}{g}(3)$

The car accelerates uniformly from rest ( $v_0=0$ ). Replacing (3) in (2), we have:

$W=\frac{wv_f^2}{2g}$

(a) Finally, we replace this in (1):

$P=\frac{wv_f^2}{2gt}\\P=\frac{9000N(20\frac{m}{s})^2}{2(9.8\frac{m}{s^2})(5.6s)}\\P=33000W$

(b)

$P=\frac{14000N(20\frac{m}{s})^2}{2(9.8\frac{m}{s^2})(5.6s)}\\P=51000W$

3 0

4 years ago

A yo-yo is made from two uniform disks, each with mass m and radius R, connected by a light axle of radius b. A light, thin stri

schepotkina [342]

Answer:

linear acceleration

$a = \frac{2g}{2 + \frac{R}{b}}$

angular acceleration

$\alpha = \frac{2g}{R(2 + \frac{R}{b})}$

Explanation:

As we know that the force due to tension force is upwards while weight of the disc is downwards

so we will have

$2mg - T = 2ma$

also we have

$Tb = (\frac{1}{2}mR^2 + \frac{1}{2}mR^2)\alpha$

now we have

$Tb = mR^2(\frac{a}{R})$

$T = \frac{mRa}{b}$

now we have

$2mg = (2ma + \frac{mRa}{b})$

$a(2 + \frac{R}{b}) = 2g$

so we have

linear acceleration

$a = \frac{2g}{2 + \frac{R}{b}}$

angular acceleration

$\alpha = \frac{2g}{R(2 + \frac{R}{b})}$

4 0

3 years ago

If a dog is accelerating at a constant rate of 6.57 m/s2, what is the mass of the dog if 25 N of force is being applied to it?

Oliga [24]

Answer:

<h3>The answer is 3.81 kg</h3>

Explanation:

The mass of the dog can be found by using the formula

$m = \frac{f}{a} \\$

f is the force

a is the acceleration

From the question we have

$m = \frac{25}{6.57} \\ = 3.80517503$

We have the final answer as

<h3>3.81 kg</h3>

Hope this helps you

8 0

3 years ago

In ice cap climates, the intense cold _____.

crimeas [40]

Answer:

A. is true

Explanation:

3 0

3 years ago

Read 2 more answers