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MArishka [77]
3 years ago
15

Which of these is a result of gravitational lensing?

Physics
1 answer:
valentina_108 [34]3 years ago
7 0

Answer:

Answer is the formation of multiple images of the same object .

Explanation:

I hope it's helpful!

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For this trajectory, what would the vertical component of acceleration for the module be at time tm=t0−σ=325s? Recall that accel
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A 1.0 m × 1.5 m double-pane window consists of two 20-mm-thick layers of glass (k = 0.78 W/m·K) that are separated by a 13-mm ai
jeka94

Answer:

\dot Q=105.042\ W is the heat loss by conduction.

Explanation:

Given:

  • area of window pane,A=1.5\ m^2
  • thickness of the glass pane, x=0.02\ mm
  • thickness of the air gap, x'=0.013\ m
  • thermal conductivity of the glass, k=0.78\ W.m^{-1}.K^{-1}
  • thermal conductivity of the air, k_a=0.025\ W.m^{-1}.K^{-1}
  • inside temperature, T_i=20^{\circ}C
  • outside temperature, T_o=-20^{\circ}C

<u>From the Fourier's law of conduction we have the rate of heat transfer as:</u>

\dot Q=k.A.\frac{dT}{dx}

\dot Q=dT\div \frac{dx}{k.A}

where:

k = thermal conductivity of the material

A = area subjected to the conduction

dT = temperature difference across the two surfaces

dx = thickness of the surface

\frac{dx}{k.A} = regarded as thermal resistance on electrical analogy

According to question here the  heat transfer occurs due to conduction of the air.

Here we have two surfaces with air sandwiched between them. So we find an equivalent resistance:

R_e=2\times \frac{x}{k.A}+ \frac{x'}{k_a.A}

R_e=2\times \frac{0.02}{0.78\times 1.5} +\frac{0.013}{0.025\times 1.5}

R_e=0.3808\ K.W^{-1}

Therefore:

\dot Q=40\div 0.3808

\dot Q=105.042\ W

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4 years ago
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Answer:

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Explanation:

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Different forces were applied to five balls, and each force was applied for the same amount of time. The data is in the table. A
Annette [7]

The magnitude of impulse on Ball A will become twice (doubles). Hence, option (c) is correct.

Impulse:

The effect of applied force acting for a very small interval of time is known as Impulse.

Given data:

The initial magnitude of the force on Ball A is, F = 50 N.

The time interval for the applied force on Ball A is, t = 1.25 s.

And the impulse at initial on ball A is, I = 62.5 N-s.

Now, if force on ball A doubles, which means new magnitude of force is,

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F' = 2 × 50

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For same time interval, the new impulse on Ball A is given as,

I' = F' × t

Solving as,

I' = 100 × 1.25

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Taking the ratio of both the impulses as,

I' / I = 125/62.5

I' = 2 I

Thus, we can conclude that the magnitude of impulse on Ball A will become twice (doubles). Hence, option (c) is correct.

Learn more about the impulse here:

brainly.com/question/904448

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