Y+x=6
y=x^2-6x+6
You would have to expand the second one.
y=x*x-6x+6
and you add all of the x's
y=-6x^3+6
y+x=6
Solve the one that's in y=mx+b form.
And you should be able to solve it from there.
Answer:
Luca bought 2 steaks and 4 watermelons.
Step-by-step explanation:
During the sale, steaks sold for $4 and watermelon sold for $3.50.
Let the number of steaks Luca bought be represented as x and the number of watermelons Luca bought be represented as y.
Luca spent $22 in total.
That means that the number of steaks that Luca bought multiplied by the price of each steaks plus the number of watermelons that Luca bought multiplied by the price of each watermelon will give $22.
In other words:
(4 * x) + (3.5 * y) = 22__________________(1)
Luca bought a total of 6 steaks and watermelons. This means that:
x + y = 6____________________________(2)
We have two simultaneous equations.
4x + 3.5y = 22 ___________(1)
x + y = 6 _______________(2)
From (2):
x = 6 - y
Putting this back in (1):
4(6 - y) + 3.5y = 22
24 - 4y + 3.5y = 22
24 - 0.5y = 22
=> 24 - 22 = 0.5y
2 = 0.5y
=> y = 2/0.5 = 4
Hence:
x = 6 - 4 = 2
Luca bought 2 steaks and 4 watermelons.
Hey your dad and dad said that she was just gonna be there and I didn’t mean that to her mom and I told you I was just saying that I was going it is answer b
Answer: A
Step-by-step explanation:
The base determines it, as if the base is less than 1, it is decreasing, and if its greater than 1, it increases
Answer:
P [ K > 3.95] = 0.5633
Step-by-step explanation:
The interpretation of the given question goes thus;
Suppose that K is a random variable
P[-3.95 ≤ K ≤ 3.95] = 0.725
where; P [ + 3.95 < K ] = P [K < - 3.95]
P[K< 3.95] - P [K > - 3.95] =0.725
P [K < 3.95] - [ 1- P[K < 3.95]] = 0.725
P[k < 3.95] - 1 + P [ K < 3.95] = 0.725
3.95 P [ K < 3.95] -1 = 0.725
3.95 P [ K < 3.95] = 1.725
P [ K < 3.95] = 1.725/3.95
P [ K < 3.95] = 0.4367
P [ K > 3.95] = 1 - P[K< 3.95]
P [ K > 3.95] = 1 - 0.4367
P [ K > 3.95] = 0.5633
