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Ronch [10]
3 years ago
6

3/5 + -1/3 = help qwq

Mathematics
1 answer:
Dmitriy789 [7]3 years ago
7 0

Answer:

the answer is

3/5-1/3=4/15

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Wildlife conservationists are concerned that the deer population might not be constant across the National Forest. The scientist
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Step-by-step explanation:.

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3 0
3 years ago
Ella was paid an 11 percent commission on the pair of shoes that she sold. The department store had paid $25 wholesale for the s
xxMikexx [17]

Answer:

The answer is B. $3.85.

Step-by-step explanation:

This is because, first if we get the percentage that the shoes were marked up by, we get that they were marked up to $35, because 40% of $25 is $10 and $25 + $10 = $35.

Then, we find the percentage of $35 that she earned. In order to do this, we see what 11% of $35 is. We get $3.85, because 10% of $35 is $3.50, and 1% of $35 is $0.35. $3.50 + $0.35 = $3.85.

This is why the answer is B. $3.85.

7 0
3 years ago
Read 2 more answers
One positive number is one-fifth of another number. the difference of the two numbers is 84. find the numbers.
seraphim [82]
Answer:  The numbers are:  " 21 " and " 105 " .
___________________________________________________
Explanation:
___________________________________________________
Let "x" be the "one positive number:

Let "y" be the "[an]othyer number".

x = 1/5 (y)
___________________________________________________
Given that the difference of the two number is "84" ;  and that "x" is (1/5) of  "y" ;  we determine that "x" is smaller than "y".

So, y − x = 84 .

Add "x" to each side of this equation; to solve for "y" in terms of "x" ;

y − x + x = 84 + x  ;

 y = 84 + x ;
___________________________________________________
So, we have: 

 x = (1/5) y ;

and:  y = 84 + x  ;

Substitute "(1/5)y" for "x" ;  in  "y = 84 + x " ;  to solve for "y" ;

 y = 84 + [ (1/5)y ]

Subtract  " [ (1/5)y ] " from EACH SIDE of the equation ;

y − [ (1/5)y ] = 84 + [ (1/5)y ] −  [ (1/5)y ]  ;

to get:

  [ (4/5)y ] = 84 ;


       ↔    (4y) / 5 = 84  ;
      
        →  4y = 5 * 84  ;

      Divide EACH SIDE of the equation by "4" ; 
to isolate "y" on one side of the equation; and to solve for "y" ;

           4y / 4 = (5 * 84) / 4 ;

                 y =  5 * (84/4) = 5 * 21 = 105 .

   y = 105 .
___________________________________________________
Now, plug "105" for "y" into:
___________________________________________________
Either:
___________________________________________________
 x = (1/5) y ;

OR:

  y = 84 + x  ;
___________________________________________________
to solve for "x" ;
___________________________________________________
Let us do so in BOTH equations; to see if we get the same value for "x" ; which is a method to "double check" our answer ;
___________________________________________________
Start with:

x = (1/5)y 

    →  (1/5)*(105) = 105 / 5 = 21 ;  x = 21 ; 

___________________________________________________
So, x = 21;  y = 105 .
___________________________________________________
Now, let us see if this values hold true in the other equation:
___________________________________________________
y = 84 + x ;

105 = ? 84 + 21 ?
 
105 = ? 105 ? Yes!
___________________________________________________
The numbers are:  " 21 " and  "105 " .
___________________________________________________

6 0
3 years ago
a radioactive sample contains 3.00 g of pure 11c, which has a half-life of 20.4 min. (a) how many moles of 11c are present initi
sveta [45]

The number of mole of pure 11C (carbon-11) initially present is 0.2727 mole

<h3>Description of mole </h3>

The mole of a substance is related to it's mass and molar mass according to the following equation

Mole = mass / molar mass

With the above formula, we can obtain the number of mole of pure 11C. Detail below:

<h3>How to determine the mole of 11C</h3>

From the question given, the following data were obtained:

  • Molar mass of 11C = 11 g/mol
  • Mass of 11C = 3 g
  • Mole of 11C =?

Mole = mass / molar mass

Mole = 3 / 11

Mole = 0.2727 mole

Therefore, the number of mole of pure 11C initially present is 0.2727 mole

Learn more about mole:

brainly.com/question/13314627

#SPJ4

8 0
2 years ago
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