Answer:
$9$
Step-by-step explanation:
Given: Thea enters a positive integer into her calculator, then squares it, then presses the $\textcolor{blue}{\bf\circledast}$ key, then squares the result, then presses the $\textcolor{blue}{\bf\circledast}$ key again such that the calculator displays final number as $243$.
To find: number that Thea originally entered
Solution:
The final number is $243$.
As previously the $\textcolor{blue}{\bf\circledast}$ key was pressed,
the number before $243$ must be $324$.
As previously the number was squared, so the number before $324$ must be $18$.
As previously the $\textcolor{blue}{\bf\circledast}$ key was pressed,
the number before $18$ must be $81$
As previously the number was squared, so the number before $81$ must be $9$.
Answer: 1) (0,-3) 2) (4,-2) 3) (2,3) 4) (-2,2)
Step-by-step explanation: Hope this helps!
The probability that he selected the special quarter is 87.5%.
<h3><u /></h3><h3><u>Probability</u></h3>
Given that Mandvil has one standard quarter and one special quarter with a Head on both sides, and he selects one of these two coins at random, and without looking at it first, he flips the coin three times, to determine, if he flips a Head three straight times, what is the probability that he selected the special quarter, the following calculation must be made:
- 1 - (standard quarter) = X
- 1 - (0.50^3) = X
- 1 - 0.125 = X
- 0.875 = X
- 0.875 x 100 = 87.5
Therefore, the probability that he selected the special quarter is 87.5%.
Learn more about probability in brainly.com/question/24217562
The answer is (x-42)×(x+42)
