1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
enyata [817]
4 years ago
6

The student in charge of the experiment wishes to present his/her findings in support of the theory that motor imagery and actio

n observation together facilitate a greater increase in motor excitability than either protocol alone.
Which of the following would be the best reason to withhold this presentation?

A. The procedure used did not include MEP recordings prior to each task.
B. MEP amplitudes in an individual are typically highly consistent.
C. The motor tasks performed in the experiment were too simple.
D. The six different conditions were run in random order.
Physics
1 answer:
Katen [24]4 years ago
3 0

Answer:

C. The motor tasks performed in the experiment were too simple.

On this case is the best option since the student wants to explain the effect of motor imagery and action observation together into the excitability. And maybe is too simple, since we need to cover other possibilities in order to analyze the excitability.

Explanation:

A. The procedure used did not include MEP recordings prior to each task.

Not true, is not a requisite record MEP prior to the task to evaluate the variable of interest on this case.

B. MEP amplitudes in an individual are typically highly consistent.

The Motor evoked potentials (MEP) "are electrical signals recorded from neural tissue or muscle after activation of central motor pathways". But on this case that's a technical aspect related to the topic and this not would be the reason why we need to withhold the presentation

C. The motor tasks performed in the experiment were too simple.

On this case is the best option since the student wants to explain the effect of motor imagery and action observation together into the excitability. And maybe is too simple, since we need to cover other possibilities in order to analyze the excitability.

D. The six different conditions were run in random order.

That's not true the student are not analyzing 6 different conditions, just 2.

You might be interested in
A child with a mass of 20 kg sits at a distance of 2 m from the pivot point of a seesaw. where should a 16-kg child sit to balan
Maksim231197 [3]
In the above problem, we need to find mass of the second child, so that the Center of Mass remains at the origin( pivot).

CM= m1r1+m2r2/m1+m2
0= 20*-2+16*r2/20+16
r2= 40/16
r2= +2.5 m

4 0
3 years ago
The record time for a Tour de France cyclist to ascend the 1100-mm-high Alpe d'Huez is 37.5 minmin. The rider and his bike had a
katen-ka-za [31]

Answer:

1945.6 W

Explanation:

We are given that

Height,h=1100 m

Time,t=37.5 min=37.5\times 60=2250 s

1 min=60 s

Mass,m=65 kg

Power,P=700 W

We have to find the his total metabolic power.

Power,=P'=\frac{W}{t}=\frac{mgh}{t}=\frac{65\times 9.8\times 1100}{2250}=311.4 W

Where g=9.8m/s^2

Efficiency =25%

Therefore,Power,P'=\frac{311.4}{0.25}=1245.6 W

Total metabolic power=P+P'=700+1245.6=1945.6 W

7 0
3 years ago
Electrical current is defined as
Dmitry_Shevchenko [17]

Explanation:

The flow of electrical charge per unit time

8 0
3 years ago
Sceiene question please show work for brainliest :)
Ad libitum [116K]

The answer to this questions would be nuclear engineer. The overall career of engineering would require physics as engineers need to know how the overall mechanics of nature affect the way their structure is built.

Hope this helped :D

5 0
4 years ago
What is the potential difference between a point 0.48 mm from a charge of 2.9 nc and a point at infinity?
Nuetrik [128]
The potential at a distance r from a charge Q is given by
V(r) = k_e  \frac{Q}{r}
where ke is the Coulomb's constant.

The charge in our problem is Q=2.9 nC=2.9 \cdot 10^{-9} C; for the point at r=0.48 mm=0.48 \cdot 10^{-3} m, the potential is
V_1 = k_e  \frac{Q}{r}= (8.99 \cdot 10^9 Nm^2 C^{-2}) \frac{2.9 \cdot 10^{-9} C}{0.48 \cdot 10^{-3} m}=  5.43 \cdot 10^4 V

For the point at infinity, we immediately see that the potential is zero, because r= \infty and so V_2 = 0.

Therefore, the potential difference between the two points is
\Delta V = V_1 - V_2 = V_1 = 5.43 \cdot 10^4 V
6 0
3 years ago
Other questions:
  • "An empty cylindrical barrel is open at one end and rolls without slipping straight down a hill. The barrel has a mass of 19.0 k
    15·1 answer
  • What career has to do with fossil fuels??
    11·1 answer
  • If an object is not accelerating, how many<br> forces act on it?
    9·2 answers
  • a machine gun fires 10 rounds per second the speed of the bullets is 300 m/s. what is the distance in the air between the flying
    12·1 answer
  • How does the suns gravitational attraction impact earths motion
    9·1 answer
  • The wave y1 = 0.12 sin π/3(5x+200t-1) propagates on a string of linear density 0.02 kg/m.
    7·1 answer
  • 1. A student gathered two boxes of the same size made of different materials: glass and clear plastic. She placed them on a wind
    12·1 answer
  • Question 8 of 10 When is there the least amount of heat transfer within a liquid? O A. When the substance changes into a gas OB.
    12·1 answer
  • A 2,100 kg car drives east toward a 55 kg shopping cart that has a velocity of 0.50 m/s west. The two objects collide, giving th
    15·2 answers
  • In a car engine, what type of energy is released at a high level, leading to inefficiency?
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!