All categories

3 years ago

How can we use thermal energy to our advantage?

Physics

2 answers:

devlian [24]3 years ago

8 0

Answer:

One of the primary advantages of thermal power is that the generation costs are extremely low. No fuel is needed to generate the power, and the minimal energy needed to pump water to the Earth's surface can be taken from the total energy yield.

Explanation:

erik [133]3 years ago

8 0

Explanation:

heating system warming homes and other buildings is an abvous way that thermal energy can be used two common types of home heating system are hot water and warm air

You might be interested in

A horizontal disk with a radius of 10 cm rotates about a vertical axis through its center. The disk starts from rest at t = 0 an

Tom [10]

Answer:

0.69s

Explanation:

10 cm = 0.1 m

Let t be the time that radial and tangential components of the linear acceleration of a point on the rim be equal in magnitude. At that time we have the angular velocity would be

$\omega = \alpha t = 2.1 t$

And so the radial acceleration is

$a_r = \omega^2 r = (2.1t)^2 r = 2.1^2 t^2 * 0.1= 0.441 t^2 m/s^2$

The tangential acceleration is always the same since angular acceleration is constant:

$a_t = \alpha * r = 2.1 * 0.1 = 0.21 m/s^2$

For these 2 quantities to be the same

$a_r = a_t$

$0.441 t^2 = 0.21$

$t^2 = 0.21/0.441 = 0.4762$

$t = \sqrt{0.4762} = 0.69 s$

6 0

3 years ago

3 small identical balls have charges -3×10^-12 ,8×10^-12 and 4×10^-12 find the charge

Norma-Jean [14]

Answer:

3×10^-12 C

Explanation:

The total of the three charges is ...

(-3 +8 +4)×10^-12 C = 9×10^-12 C

Assuming the charge is equally distributed between the balls when they are brought in contact, the charge on each ball will be ...

(9/3)×10^-12 C = 3×10^-12 C

7 0

2 years ago

Un pintor de 75.0 kg sube por una escalera de 2.75 m que está inclinada contra una pared vertical. La escalera forma un ángulo d

dezoksy [38]

Answer:

Work done, W = 1786.17J

Explanation:

The question says "A 75.0-kg painter climbs a 2.75-m ladder that is leaning against a vertical wall. The ladder makes an angle of 30.0 ° with the wall. How much work (in Joules) does gravity do on the painter? "

Mass of a painter, m = 75 kg

He climbs 2.75-m ladder that is leaning against a vertical wall.

The ladder makes an angle of 30 degrees with the wall.

We need to find the work done by the gravity on the painter.

The angle between the weight of the painter and the displacement is :

θ = 180 - 30

= 150°

The work done by the gravity is given by :

$W=Fd\cos\theta\\\\=75\times 10\times 2.75\times \cos30\\\\=1786.17\ J$

Hence, the required work done is 1786.17 J.

6 0

2 years ago

* Check all of the things that can affect power Time Work Distance Force

gladu [14]

Answer:

fhddmvxmvydlyghclhchc

3 0

2 years ago

S waves arrive at distant points before other seismic waves, true or false

Step2247 [10]

False. p waves, than s waves

3 0

3 years ago