Substitute the value of the variable into the expression and simplify, its theta arrow-to-the-right, pi/4 times 1-tan theta/sin theta - cos theta (i cant type the signs on computer, sorry
They are all true None are false
Answer:
2.83 s
Step-by-step explanation:
We are given that
![h(t)=-16t^2+10t+100](https://tex.z-dn.net/?f=h%28t%29%3D-16t%5E2%2B10t%2B100)
When a rock reached the ground then h(t)=0
![-16t^2+10t+100=0](https://tex.z-dn.net/?f=-16t%5E2%2B10t%2B100%3D0)
![16t^2-10t-100=0](https://tex.z-dn.net/?f=16t%5E2-10t-100%3D0)
Using quadratic formula
![x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-b%5Cpm%5Csqrt%7Bb%5E2-4ac%7D%7D%7B2a%7D)
![t=\frac{10\pm\sqrt{(-10)^2-4\times 16\times (-100)}}{2(16)}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B10%5Cpm%5Csqrt%7B%28-10%29%5E2-4%5Ctimes%2016%5Ctimes%20%28-100%29%7D%7D%7B2%2816%29%7D)
![t=\frac{10\pm\sqrt{100+6400}}{32}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B10%5Cpm%5Csqrt%7B100%2B6400%7D%7D%7B32%7D)
![t=\frac{10+\sqrt{6500}}{32}=2.83](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B10%2B%5Csqrt%7B6500%7D%7D%7B32%7D%3D2.83)
![t=\frac{10-\sqrt{6500}}{32}=-2.2](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B10-%5Csqrt%7B6500%7D%7D%7B32%7D%3D-2.2)
Time cannot be negative .Therefore, negative value of t can not be possible.
Hence, the rock takes 2.83 sec to reach the ground.
Answer:
2m + 4 = 5
Step-by-step explanation:
Cross multiply.
2(m + 2) = 5 * 1
2m + 4 = 5
Answer: 2m + 4 = 5
Answer:
i = -7/12
Step-by-step explanation:
(-3/4 + 4/3) + i = 0
(-9/12 + 16/12) + i = 0
7/12 + i = 0
i = -7/12