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3 years ago

6

During soccer practice, Maya kicked a soccer ball 37° off the ground at 25 m/s. What was the ball's speed 2.2 s after she kicked

it?

1 answer:

ki77a [65]3 years ago

5 0

<u>Answer</u>

3.44 m/s

<u>Explanation</u>

The motion apply the equations of Newton's law of motion. The ball is acceleration is -9.8 m/s² (acceleration due to gravity. It is negative because the ball is going against gravity, so it is decelerating).

The first equation of Newton's law of motion is;

V = U + at

Where V is the final velocity, U is the initial velocity, a is acceleration and t the time taken.

V = 25 + (-9.8 × 2.2)

= 25 - 21.56

= 3.44 m/s

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Answer:

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the data we have is:

mass: $m=22kg$

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Vertically the forces acting on the object:

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now let's analyze the horizontal forces

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$F=ma_{x}=F-f\\ma_{x}=F-\mu mg$

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Answer:

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