Answer:
20 mi
Exp3tanation:
I did the same question in a quizz
Answer:
c.) 36E
Explanation:
The magnitude of the electric field is given by the expression
(1)
where k is the Coulomb's constant, q is the charge that generates the field, and d is the distance from the charge.
In this problem, we have that the magnitude of the field at a distance d is 4E, so we can rewrite the previous equation as

Now we want to determine the electric field at a distance of
away. Substituting into (1), we find
(2)
We also know that
(3)
So combining (2) with (3), we find a relationship between the original field and the new field:

Answer:
70.9pi rad/s
Explanation:
angle turned through = 16
angular acceleration = 22.6 rad/s2
angular speed = 10.2 rad/s
time = ?
angular acceleration = angular speed/time
time = 10.2/22.6
time = <u>0</u><u>.</u><u>4</u><u>5</u><u> </u><u>s</u><u>e</u><u>c</u><u>o</u><u>n</u><u>d</u><u>s</u>
<u>angular speed</u><u> </u><u>=</u><u> </u><u>a</u><u>n</u><u>g</u><u>l</u><u>e</u><u> </u><u>t</u><u>u</u><u>r</u><u>n</u><u>e</u><u>d</u><u> </u><u>t</u><u>h</u><u>r</u><u>o</u><u>u</u><u>g</u><u>h</u><u>/</u><u>t</u><u>i</u><u>m</u><u>e</u>
<u>angular speed</u><u> </u><u>=</u> (16 × 2pi)/0.45
= 70.9pi rad/s
The time of motion of the object at the given speed and distance is 4 seconds.
<h3>Time of motion of the object</h3>
The time of motion of the object is calculated as follows;
t = d/v
where;
- d is distance = 10 m
- v is speed = 2.5 m/s
- t is time of motion
t = 10/2.5
t = 4 s
Thus, the time of motion of the object at the given speed and distance is 4 seconds.
Learn more about time here: brainly.com/question/2854969
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A force is a push or pull upon an object resulting from the object's interaction with another object. Whenever there is an interaction between two objects, there is a force upon each of the objects. When the interaction ceases, the two objects no longer experience the force. Forces only exist as a result of an interaction