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Amanda [17]
3 years ago
6

A battery does 2.186 J of work to transfer 0.033 C of charge from the negative to the positive terminal. What is the emf of this

battery?
Physics
1 answer:
sladkih [1.3K]3 years ago
4 0

Answer:

66.24 Volts

Explanation:

W = Amount of work done in moving the charge from negative to positive terminal = 2.186 J

Q = Amount of charge being moved from negative to positive charge = 0.033 C

ΔV = EMF of the battery

Amount of work done in moving the charge from negative to positive terminal is given as

W = Q ΔV

2.186 = (0.033) ΔV

ΔV = 66.24 Volts

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2 years ago
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5 0
3 years ago
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I need a diagram to label these parts.

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