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Amanda [17]
3 years ago
6

A battery does 2.186 J of work to transfer 0.033 C of charge from the negative to the positive terminal. What is the emf of this

battery?
Physics
1 answer:
sladkih [1.3K]3 years ago
4 0

Answer:

66.24 Volts

Explanation:

W = Amount of work done in moving the charge from negative to positive terminal = 2.186 J

Q = Amount of charge being moved from negative to positive charge = 0.033 C

ΔV = EMF of the battery

Amount of work done in moving the charge from negative to positive terminal is given as

W = Q ΔV

2.186 = (0.033) ΔV

ΔV = 66.24 Volts

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vovangra [49]

Answer:

acceleration 8 km/h/s south

Explanation:

First of all, let's remind that a vector quantity is a quantity which has both a magnitude and a direction.

Based on this definition, we can already rule out the following two choices:

distance: 40 km

speed: 40 km/h

Since they only have magnitude, they are not vectors.

Then, the following option:

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So, the correct choice is

acceleration 8 km/h/s south

In fact, the acceleration can be calculated as

a=\frac{v-u}{t}

where

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u = 0 is the initial velocity

t = 5 s is the time

Substituting,

a=\frac{40 km/h-0}{5 s}=8 km/h/s

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7 0
4 years ago
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0 Newtons

Explanation:

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mass = 1200 kg

acceleration = 0

F  = (1200)(0) = 0

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3 years ago
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