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erastovalidia [21]
2 years ago
8

The magnetic circuit below is excited by a 100-turn coil wound over the central leg. The mean length of the central leg is 5.5cm

; the mean length of outer paths (including the part of the iron bar at the bottom) is 15.5cm. The relative permeability of the magnetic material is 2000. The cross-sectional area of all legs is A
Physics
1 answer:
Dafna11 [192]2 years ago
3 0

Answer:

Hello your question is incomplete attached below is the complete question and solution

<em>answer; </em>

attached below

Explanation:

<em>Given data:</em>

100-turn coil

mean length of central leg = 5.5 cm

mean length of outer paths = 15.5 cm

relative permeability = 2000

cross sectional area ( A ) = 1 cm^2

distance x = 1 cm  

attached below is a detailed solution

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A scientific _______ is a principle that describes the behavior of a natural phenomenon. A. Model. B. law. C. theory d. Analysis
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When two resistors are wired in series with a 12 V battery, the current through the battery is 0.33 A. When they are wired in pa
Tcecarenko [31]

Answer:

If R₂=25.78 ohm, then R₁=10.58 ohm

If R₂=10.57 then R₁=25.79 ohm

Explanation:

R₁ = Resistance of first resistor

R₂ = Resistance of second resistor

V = Voltage of battery = 12 V

I = Current = 0.33 A (series)

I = Current = 1.6 A (parallel)

In series

\text{Equivalent resistance}=R_{eq}=R_1+R_2\\\text {From Ohm's law}\\V=IR_{eq}\\\Rightarrow R_{eq}=\frac{12}{0.33}\\\Rightarrow R_1+R_2=36.36\\ Also\ R_1=36.36-R_2

In parallel

\text{Equivalent resistance}=\frac{1}{R_{eq}}=\frac{1}{R_1}+\frac{1}{R_2}\\\Rightarrow {R_{eq}=\frac{R_1R_2}{R_1+R_2}

\text {From Ohm's law}\\V=IR_{eq}\\\Rightarrow R_{eq}=\frac{12}{1.6}\\\Rightarrow \frac{R_1R_2}{R_1+R_2}=7.5\\\Rightarrow \frac{R_1R_2}{36.36}=7.5\\\Rightarrow R_1R_2=272.72\\\Rightarrow(36.36-R_2)R_2=272.72\\\Rightarrow R_2^2-36.36R_2+272.72=0

Solving the above quadratic equation

\Rightarrow R_2=\frac{36.36\pm \sqrt{36.36^2-4\times 272.72}}{2}

\Rightarrow R_2=25.78\ or\ 10.57\\ If\ R_2=25.78\ then\ R_1=36.36-25.78=10.58\ \Omega\\ If\ R_2=10.57\ then\ R_1=36.36-10.57=25.79\Omega

∴ If R₂=25.78 ohm, then R₁=10.58 ohm

If R₂=10.57 then R₁=25.79 ohm

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A painter lifts a 3 kg can of paint 3 m above the floor. How much work was done?
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Hey there!


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TobeySnaps.

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