A 100 N force is applied to a 500 kg crate resting on frictionless wheels.
2 answers:
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From the momentum conservation we know that the initial momentum is equal to the final momentum. The momentum in a singular way can be defined as the product between the mass and the velocity of an object. In the presented system, however, there are two objects, therefore the mass of both and the speed of both, before and after the collision must be taken into account. Mathematically we could describe this as
Here,
= Mass of each object
= Initial velocity of each object
= Final velocity of each object
From here we can realize that it is necessary to use the system on both cars to be able to predict what will happen either with their masses, or their speeds.
The correct answer is C.
Answer:
The value is
Explanation:
From the question we are told that
The mass of the car is
The acceleration is
Generally the net force applied on the rope is mathematically represented as
Here W is the weight of the car which is evaluated as
=>
=>
Generally the net force can also be mathematically represented as
So
=>
=>
The change in kinetic energy is
Explanation:
According to the work-energy theorem, the work done on an object is equal to the change in kinetic energy of the object. Mathematically:
where :
W is the work done on the object
is the final kinetic energy of the object
is the initial kinetic energy
Also, the work done on an object is (assuming that the force is applied parallel to the motion of the object):
where
F is the magnitude of the force
is the displacement of the object
In this problem, the force acting on the object is
F
While the displacement is the horizontal distance travelled, so
Therefore, the work done is
And so the change in kinetic energy is
Learn more about work and kinetic energy:
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