Answer:
10%
Explanation:
Efficiency = work done / energy used
e = (10 m × 100 N) / (10,000 J)
e = 0.1
The efficiency is 0.1, or 10%.
Answer:
A) 29.4 m 17.0 m; B) 2 m
Explanation:
If a vector is 34.0 m in length and is directed 60.0° east of north (which means 30.0° over the horizontal), then its coordinates will be:
Horizontal: (34.0 m)cos(30.0°)=29.4 m
Vertical: (34.0 m)sin(30.0°)=17 m
If one person walks 8.0 meters in a straight line and then walks 5.0 meters in another straight line, then the minimum displacement would be to go back over his tracks, displacing himself 8m-5m=3m, while the maximum displacement would be going straight ahead, displacing himself 8m+5m=13m. Any answer outside this interval is impossible (2m).
The Normal Force = M x G x Cos(theta)
= 9.5 Kg x 9.8 m/s^2 x cos 23
= 9.5 Kg x 9.8 m/s^2 x 0.9205
Converting Kg to Newton,
1 Kg = 9.81 N
= 9.5 Kg x 9.81 N x 9.8 m/s^2 x 0.9205
= 840.702 N
19.8 N force is tending to lift Rover vertically off the ground.
<h3>What is horizontal and vertical component?</h3>
The horizontal velocity component (
) describes the influence of the velocity in displacing the projectile horizontally. The vertical velocity component (
) describes the influence of the velocity in displacing the projectile vertically.
According to the question,
The women pulls the dog with a force of 30 N at an angle of 29° from the horizontal.
Horizontal component= 30cos(29°) = 22.2 N
Vertical component = 30sin(29°) = 19.8 N
Therefore,
The horizontal component would tend to make the dog move forward and the vertical component would tend lift it off the ground.
Hence,
19.8 N force is tending to lift Rover vertically off the ground.
Learn more about horizontal and vertical component here:
brainly.com/question/11776718
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<span>The correct answer is D) 12 protons and no electrons. This is correct because the number of protons in the nucleus of the atom is 12. The number of protons in the nucleus represents the atomic number. Therefore if there are 12 protons in the nucleus, the atomic number is 12.</span>
