(6) 70, 70, 110
∠2 = ∠4 = 110° ( congruent angles )
∠3 = 180° - 110° = 70° ( straight angle )
∠1 = 70° ( vertically opposite ∠3 )
(9) ∠AEC = 15x - 11
since EC bisects ∠BED then ∠BEC = ∠CED = 4x + 1
∠AEC = ∠AEB + ∠BEC = 11x - 12 + 4x + 1 = 15x - 11
(7) x = 3
AC = AB + ABC = 32
2x + 6x + 8 = 32
8x + 8 = 32 ( subtract 8 from both sides )
8x = 24 ( divide both sides by 8 )
x = 3
<span>C.∠GFE Is the answer.</span>
We will use certain constraints to imitate the repetition of the process as mentioned below
To simulate one repetition of the procedure using random digits, we shall perform as follows:
from a line of the random digits table, ten one and two-digit numbers could be selected with the following conditions;
1. skipping repeated numbers
2. skipping numbers from 77 to 99
here the numbers 01 to 12 i.e. first-class passengers in the group of selected random numbers are to be counted.
As we know, numbers represent first-class passengers while numbers to represent coach-class people.
Hence, using this we can use random digits
Learn more about variables:
brainly.com/question/17344045
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Answer:
1 (7/45)
Step-by-step explanation:
you'll see how many 45 can go into 52. Only 1 45 can fit into 52 with some leftover.
so to find the left over numbers you'll subtract 45 from 52= 7
so 7/45 is left over
Answer:
The answer is 3/196
Step-by-step explanation:
ok so there are 3 types of marbles so...
1.) 3/?
2.) you add the marbles up (79 + 76 + 41) = 196
3.) you get... 3/196 of a chance
