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pochemuha
3 years ago
13

Solve algebraically for all values of x

Mathematics
1 answer:
nikitadnepr [17]3 years ago
4 0
1) cross multiply both sides.
3x^2-24= 2x^2+10
x^2-10x-24=0
x^2-12x+2x-24=0
x(x-12)+2(x-12)=0
(x-12) (x+2)=0
Bring -12 and 2 to the other side. Therefore the value of x are 12 and -2.
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