Answer:
Area of the regular dodecagon inscribed in a circle will be 27 square units.
Step-by-step explanation:
A regular dodecagon is the structure has twelve sides and 12 isosceles triangles inscribed in a circle as shown in the figure attached.
Since angle formed at the center by a polygon = 
Therefore, angle at the center of a dodecagon =
= 30°
Since one of it's vertex is (3, 0) therefore, one side of the triangle formed or radius of the circle = 3 units
Now area of a small triangle = 
where a and b are the sides of the triangle and θ is the angle between them.
Now area of the small triangle = 
= 
Area of dodecagon = 12×area of the small triangle
= 12×
= 27 unit²
Therefore, area of the regular octagon is 27 square unit.
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Your answer would be: m = 63/4 in fraction form and m = 15.75 in decimal form.
Hope this helps and happy holidays!!
-3x, -x + 1/2, 2x, 10x if you need anything else feel free to ask. I would like brainliest but if not its ok
We have that
2r−9≤−6------> 2r ≤ -6+9-------> 2r ≤ 3-----> r ≤ 1.5
the solution is the interval (-∞, 1.5]
using a graph tool
see the attached figure