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pochemuha
4 years ago
13

Solve algebraically for all values of x

Mathematics
1 answer:
nikitadnepr [17]4 years ago
4 0
1) cross multiply both sides.
3x^2-24= 2x^2+10
x^2-10x-24=0
x^2-12x+2x-24=0
x(x-12)+2(x-12)=0
(x-12) (x+2)=0
Bring -12 and 2 to the other side. Therefore the value of x are 12 and -2.
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Step-by-step explanation:

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is interest per 1 year? if so:

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The marital status distribution of the U.S. male population, ages 15 and older, is as follows: 35.4% never married, 53.6% marrie
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The hypothesis illustrates that the males in the group don't follow a same distribution as all the males that are in the United States.

<h3>How to illustrate the information?</h3>

Based on the information given, it should be noted that the degree of freedom given in this case will be:

= 4 - 1

= 3

By using the Excel function, the p-value is given as 0.0002. In this case, we've to reject the null hypothesis if the p value is less than 0.1.

Therefore, we will reject the null hypothesis in this case. In inferential statistics, the null hypothesis is that two possibilities are the same. It is observed difference is due to chance alone. Using statistical tests, it is possible to calculate the likelihood that the null hypothesis is true

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Emily has pennies and five dollar bills in her pocket. The number of pennies is eight less than three times the number of five d
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A triangular lot has sides of 215m, 185m, and 125m. Find the measures of the angles at its corners
Vlada [557]

Answer:

The measures of the angles at its corners are 59.1\°,35.4\°,85.5\°

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

Find the measure of angle A

Applying the law of cosines

185^{2}= 215^{2}+125^{2}-2(215)(125)cos(A)

2(215)(125)cos(A)= 215^{2}+125^{2}-185^{2}

cos(A)= [215^{2}+125^{2}-185^{2}]/(2(215)(125))cos(A)=0.513953

A=arccos(0.513953)=59.1\°

step 2

Find the measure of angle B

Applying the law of cosines

125^{2}= 215^{2}+185^{2}-2(215)(185)cos(B)

2(215)(185)cos(B)= 215^{2}+185^{2}-125^{2}

cos(B)= [215^{2}+185^{2}-125^{2}]/(2(215)(185))cos(B)=0.81489

B=arccos(0.81489)=35.4\°

step 3

Find the measure of angle C

Applying the law of cosines

215^{2}= 125^{2}+185^{2}-2(125)(185)cos(C)

2(125)(185)cos(C)= 125^{2}+185^{2}-215^{2}

cos(C)= [125^{2}+185^{2}-215^{2}]/(2(125)(185))cos(C)=0.0784

C=arccos(0.0784)=85.5\°

3 0
3 years ago
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