4 years ago

Solve algebraically for all values of x

1 answer:

4 0

1) cross multiply both sides.
3x^2-24= 2x^2+10
x^2-10x-24=0
x^2-12x+2x-24=0
x(x-12)+2(x-12)=0
(x-12) (x+2)=0
Bring -12 and 2 to the other side. Therefore the value of x are 12 and -2.

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