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vodomira [7]
3 years ago
14

Which of the following statements best describes the carbon atoms present in grass-eating cows?

Biology
1 answer:
Temka [501]3 years ago
4 0

Answer:

d. The carbon atoms came from carbon dioxide and were incorporated into sugars through photosynthesis in the grass.

Explanation:

Grass eating cows are heterotrophs and can not synthesize the organic sugars by themselves. They derive it from grasses they eat.  

Grasses are the autotrophs that can fix atmospheric carbon dioxide into glucose in the presence of sunlight by the process of photosynthesis. The extra glucose formed during photosynthesis is stored in the cells of grasses in the form of starch and becomes a source of carbon for herbivores such as cows.  

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A researcher collected a single-celled organism from birdbath water and grew the organism in a laboratory. The researcher observ
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Answer: The organisms exhibit a form of Asexual reproduction.

Explanation:

This is a form of asexual reproduction because Asexual reproduction is a form of reproduction where a single celled organisms or muiticellular organisms produce or divide to produce offsprings that are genetically identical without fusion of gametes and exchange of genetic materials.

This type of reproduction includes binary fission( where an organism divides into two), fragmentation( where an organism divides into fragments), budding, spore formation e.t.c.

8 0
3 years ago
Cell division is represented where
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Answer:

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Explanation:

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3 years ago
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Starch (a polymer in glucose)
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3 years ago
Python allows you to compare strings, but it is not case sensitive.
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5 0
4 years ago
A sand storage tank used by the highway department for winter storms is leaking. As the sand leaks out, it forms a conical pile.
harina [27]

Answer:

Rate of change of volume of the pile  = 54\pi

Explanation:

Given -

Rate of increase of the base of the pile = 0.75 inches per minute

Height of the pile = 2 * the radius of the base

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Then h = 2* r

Radius "r" = 6 inches

Rate of change of radius i.e

\frac{dr}{dt} = 0.75

Volume of conical pile

\frac{\pi }{3} * r^2 * h\\= \frac{\pi }{3} * r^2 * 2 * r\\= \frac{\pi }{3} *2* r^3

Change in volume of conical pile

\frac{dV}{dt} =  \frac{dr}{dt}  * \frac{6* \pi * r^2 }{3}

Substituting the value of rate of change of radius, we get -

\frac{dV}{dt}  = 2 * \pi * (6^2) * (0.75)\\\frac{dV}{dt}  = 54 \pi

Rate of change of volume of the pile  = 54\pi

8 0
3 years ago
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