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Veronika [31]
3 years ago
10

Negative 5 is fewer than 6 less than a number k

Mathematics
1 answer:
lara [203]3 years ago
7 0

Answer:

k > 1 is the solution.

Step-by-step explanation:

We are given that 'Negative 5 is fewer than 6 less than a number k', so algebraically it means that - 5 < k - 6.

Then this is a linear inequality of single variable k and we have to solve it.

Now, we have

- 5 < k - 6

⇒ - 5 + 6 < k - 6 + 6 {Adding 6 to both sides}

⇒ 1 < k

⇒ k > 1

This is the solution of the given inequality. (Answer)

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<h3> - - - - - - - - - - - - - ~<u>Hello There</u>!~ - - - - - - - - - - - - - </h3>

➷ First, we need to figure out the total number of candies:

3 + 4 + 3 + 2 = 12

Keep this number in mind as it will be the denominator

There are 3 yellow candies so the probability would be:

\frac{3}{12} or \frac{1}{4}

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3 years ago
5a+18≤6(a+3)-a . the solution in set builder notation
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Answer:

{a | always(true)}

Step-by-step explanation:

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8 0
3 years ago
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What is the value of x? Show work.
ella [17]

Answer:

x=5

Step-by-step explanation:

This is because the inscribed angle of the circle or angle EFG is equal to the twice of the degree of the arc EG. Therefore, we can create this equation:

12+40=2(8x+10)

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5 0
3 years ago
PLS HELPPPP MEEEE I NEED WORK SHOWN TOO
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The series of operations for each case are listed below:

  1. GCF / GCF / GCF
  2. GCF / Grouping
  3. Quadratic trinomial
  4. GCF / Quadratic trinomial
  5. Difference of squares
  6. Difference of cubes / Quadratic trinomial
  7. Sum of cubes
  8. GCF / Quadratic trinomial
  9. GCF / Difference of squares

<h3>How to applying factor properties to simplify algebraic expressions</h3>

In algebra, factor properties are commonly used to solve certain forms of polynomials in a quick and efficient way and whose effectiveness is sustained on all definitions and theorems known in real algebra. In this problem, we should explain and show what factor properties are used in each case:

Case 1

5 · x · y³ + 10 · x² · y                                             Given

5 · (x · y³ + 2 · x² · y)                                            GCF

5 · x · (y³ + 2 · x · y)                                              GCF

5 · x · y · (y² + 2 · x)                                              GCF

Case 2

6 · z · x + 9 · x + 14 · z + 21                                   Given

3 · x · (z + 3) + 7 · (z + 3)                                       GCF

(3 · x + 7) · (z + 3)                                                  Grouping

Case 3

a² + 2 · a - 63                                                       Given

(a + 9) · (a - 7)                                                       Quadratic trinomial

Case 4

6 · z² + 5 · z - 4                                                     Given

6 · [z² + (5 / 6) · z - 2 / 3]                                      GCF

6 · (z - 1 / 2) · (z + 4 / 3)                                         Quadratic trinomial

Case 5

81 · m² - 25                                                           Given

(9 · m + 5) · (9 · m - 5)                                           Difference of squares

Case 6

8 · x³ - 27                                                               Given

(2 · x - 3) · (4 · x² + 6 · x + 9)                                  Difference of cubes

4 · (2 · x - 3) · [x² + (3 / 2) · x + 9 / 4]                      Quadratic trinomial

Case 7

27 · b³ + 64 · z³                                                      Given

(3 · b + 4 · z) · (9 · b² - 12 · b · z + 16 · z²)               Sum of cubes

Case 8

2 · w³ - 28 · w² + 80 · w                                         Given

2 · w · (w² - 14 · w + 40)                                          GCF

2 · w · (w - 4) · (w - 10)                                             Quadratic trinomial

Case 9

200 · a⁴ - 18 · b⁶                                                     Given

2 · (100 · a⁴ - 9 · b⁶)                                                GCF

2 · (10 · a² + 3 · b³) · (10 · a² - 3 · b³)                       Difference of squares

To learn more on polynomials: brainly.com/question/17822016

#SPJ1

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