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musickatia [10]
3 years ago
11

I WILL GIVE YOU BRAINLIEST FOR THIS ONE

Mathematics
1 answer:
lakkis [162]3 years ago
8 0
The first one doesn’t represent a function. This is because it uses the same x-value twice.
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Jeffrey needs $200 to buy a new iPod. Right now, he has $75. What percent of the $200 does he have?
melisa1 [442]

Answer:

40%

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Which statement about 3 multiplied by 23 must be true?
kumpel [21]

Answer:

(C) because the answer is 69

Step-by-step explanation:

you make 3 groups of 23 and u get 69

its greater then 23 and 4

and its not between 3 and 4 or between 23 or 3

so it can only be (C)

9 0
2 years ago
L what is 67000 rounded to the nearest ten thousand
Aleks04 [339]

The next larger ten thousand is  70,000 .
The next smaller ten thousand is  60,000 .
67,000  is closer to  70,000  than it is to  60,000 .
So  70,000  is the nearest ten thousand.

8 0
3 years ago
Read 2 more answers
Let N be the universal set and A, B, C, D be its subsets given by A={x:xisaevennaturalnumber},B={x:xNandxisamultipleof3} C={x:x
Svet_ta [14]

Answer:

A^{'} = {1,3,5,7,9,....}

B^{'} = {1,2,4,5,7,8,10,11,13,14......}

C^{'} = {1,2,3,4,5}

D^{'} = {10,11,12,13,14,15,......}

Step-by-step explanation:

Solution:

It is given that, Universal set is the set of all Natural Numbers.

and

Set A, Set B, Set  C, Set D are subsets of Universal set.

A = {x:x is even natural numbers} = {2,4,6,8,10,.....}

B = {x:x ∈ N and x is a multiple of 3} = {3,6,9,12,15,....}

C = {x:x∈ N and x < 5} = {6,7,8,9,10,.....}

D = {x:x ∈ N and x > 10} = {1,2,3,4,5,6,7,8,9}

U = {1,2,3,4,5,6,7,8,9,10,11,........}

Complements:

A^{'} = U-A = {1,2,3,4,5,6,7,8,9,10,11,........} - {2,4,6,8,10,.....}

A^{'} = {1,3,5,7,9,....}

B^{'} = U-B =  {1,2,3,4,5,6,7,8,9,10,11,........} - {3,6,9,12,15,....}

B^{'} = {1,2,4,5,7,8,10,11,13,14......}

C^{'} = U-C = {1,2,3,4,5,6,7,8,9,10,11,........} - {6,7,8,9,10,.....}

C^{'} = {1,2,3,4,5}

D^{'} = {1,2,3,4,5,6,7,8,9,10,11,........} - {1,2,3,4,5,6,7,8,9}

D^{'} = {10,11,12,13,14,15,......}

8 0
3 years ago
If 3,000 bacteria, with a growth constant (k) of 2.8 per hour, are present at the beginning of an experiment, in how many hours
Ivenika [448]

Given:

Initial number of bacteria = 3000

With a growth constant (k) of 2.8 per hour.

To find:

The number of hours it will take to be 15,000 bacteria.

Solution:

Let P(t) be the number of bacteria after t number of hours.

The exponential growth model (continuously) is:

P(t)=P_0e^{kt}

Where, P_0 is the initial value, k is the growth constant and t is the number of years.

Putting P(t)=15000,P_0=3000, k=2.8 in the above formula, we get

15000=3000e^{2.8t}

\dfrac{15000}{3000}=e^{2.8t}

5=e^{2.8t}

Taking ln on both sides, we get

\ln 5=\ln e^{2.8t}

1.609438=2.8t                  [\because \ln e^x=x]

\dfrac{1.609438}{2.8}=t

0.574799=t

t\approx 0.575

Therefore, the number of bacteria will be 15,000 after 0.575 hours.

4 0
2 years ago
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