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Varvara68 [4.7K]
4 years ago
13

A mechanical engineer wishes to compare strength properties of steel beams with similar beams made with a particular alloy. The

same number of beams, n, of each type will be tested. Each beam will be set in a horizontal position with a support on each end, a force of 2500 lb will be applied at the center, and the deflection will be measured. From past experience with such beams, the engineer is willing to assume that the true standard deviation of deflection for both types of beam is 0.06 in. Because the alloy is more expensive, the engineer wishes to test at level 0.01 whether it has smaller average deflection than the steel beam. What value of n is appropriate if the desired type II error probability is 0.05 when the difference in true average deflection favors the alloy by 0.05 in.? (Round your answer up to the next whole number.)
Mathematics
1 answer:
Annette [7]4 years ago
4 0

Answer:

50

Step-by-step explanation:

Level of significance, a = 0.01

Type II error probability, b =0.05

From the z-table:

the critical value at 1% level of significance, Zα = Z0.01 = 2.33

the critical value at 5% probability, Zβ = Z0.05 = 1.645

The critical value of z can be obtained from the standard normal table using the desired level of significance and the tail of test.  

The critical value tells the number of standards deviations away is the result from the mean.

Probability of type I error denoted by  a

Probability of type II error denoted by b.

Type I error is to falsely infer the existence of something that is not there, while a type II error is to falsely infer the absence of something that is.

From the given information,

a=0.01, b=0.05, o1 = o2 =0.05, Dο = 0, D' = 0.04

The sample size is calculated as,

n = ( o^2 + o2^2) * (Za +Zb)^2 /( (D' - D0)^2)

= (0.05^2 +0.05^2)*(2.33 + 1.645)^2 / (0.04 - 0)^2

= 49.38

which is 50 [Rounded to next integer]

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How does the job satisfaction score for weeks 5-8 compare to weeks 1-4?
MrRa [10]

The correct comparison for Weeks 5-8 is higher than Week 1-4, hence, the job satisfaction for Week 5-8 is 17% higher.

<u>Job Satisfaction Score</u> :

  • Week 1 = 3.50
  • Week 2 = 3.40
  • Week 3 = 3.30
  • Week 4 = 3.60
  • Week 5 = 4.20
  • Week 6 = 4.00
  • Week 7 = 4.10
  • Week 8 = 3.90

<u>Job Satisfaction for week 1 - 4</u> :

  • Week 1 + Week 2 + Week 3 + Week 4
  • (3.50 + 3.40 + 3.30 + 3.60) = 13.80

<u>Job Satisfaction for Week 5 - 8</u> :

  • Week 5 + Week 6 + Week 7 + Week 8
  • (4.20 + 4.00 + 4.10 + 3.90) = 16.20

<u>Difference</u><u> between the two categories</u> :

[(Week 5 - 8) - (Week 1-4)] / Week 1-4] × 100%

(16.20 - 13.80) / 13.80 × 100%

(2.4 / 13.80) × 100%

0.1739 × 100%

= 17.39%

Therefore, the job satisfaction for Week 5 - 8 is about 17% higher than Week 1 - 4

Learn more :brainly.com/question/13218948

8 0
3 years ago
The mean annual tuition and fees for a sample of 14 private colleges in California was $37,900 with a standard deviation of $7,2
JulijaS [17]

Answer:

Z_{0.005}>Z H₀ is wrong and other is correct. IT means $35000 is not mean value.

Step-by-step explanation:

Two hypothesis:

H₀=$35,000

Hₐ≠$35,000

Test Formula:

Z=\frac{(X-u)}{\frac{S}{\sqrt{n} } }

Where:

X is the mean value=$37,900

u is the value with 0.01 significance=$35000

S is the standard deviation

n is the sample size

Z=\frac{(37900-35000)}{\frac{7200}{\sqrt{14} } }

Z=1.507

Z with 0.01 significance:

0.01/2=0.005=0.05%

Degrees of freedom=14-1=13

From t distribution table at 0.05% and 13 dof:

Z_{0.005}=4.221

So

Z_{0.005}>Z H₀ is wrong and other is correct. IT means $35000 is not mean value.

7 0
4 years ago
Please help!!! Thanks!
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8x+(4*30)=6(6+30)
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3 years ago
The teacher decides that no student can win twice, so she removes the tickets of the first winner before drawing the second winn
trasher [3.6K]

Answer:

3/4

Step-by-step explanation:

Take Kitzen's number of raffle tickets and put them over Ava's tickets to give you 12/16 and the simplify which gives you 3/4 because the fraction is divisible by 4.

4 0
3 years ago
A boat goes 4 miles upstream in four hours. It returns downstream to the starting point in two hours .The rate of the boat is X.
Anna71 [15]
The boat(x) goes 1mi/hr because 4 mi and 4hr divide each by four. The rate of the river current S twice that because the time is halved so y=8mi/hr
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