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marshall27 [118]
3 years ago
5

H2O (s) ⇒ H2O What would be the best argument against writing this in the form of a chemical equation?

Chemistry
1 answer:
Goshia [24]3 years ago
5 0

Answer: Since this is merely a Physical Change, it is improper to write it as a chemical equation.

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Determine the molarity of 56.00 grams of aluminum nitrate in 450 milliliters of solution?
SVETLANKA909090 [29]

Answer:

4.62 M

Explanation:

Molarity = moles/volumes (L), so you need to find the moles and the volumes in liters.

Finding the volume is easy because you just have to convert mL to L, so the volume is 0.45 L

Next, find the moles. You can do this by using the molar mass of aluminum to convert the grams to moles. The molar mass of aluminum is 26.98 g/mol.

56 g * (1 mol/26.98 g) = 2.08 mol

Now, divide the moles (2.08) by the volume (.45 L)

Molarity = 4.62 M

3 0
3 years ago
Nitrogen - 14.0067
alina1380 [7]

Answer:

potasium to erbium

Explanation:

3 0
3 years ago
Please help i am striggling with science so bad
Dennis_Churaev [7]

well, yes it will continue to swing but not forever. it will just a long time but eventually stop. the reason is because of the air resistance which will continue to damp the motion until the bob stops

3 0
3 years ago
A 20.00-mL sample of a weak base is titrated with 0.0568 M HCl. At the endpoint, it is found that 17.88 mL of titrant was used.
nata0808 [166]

Answer: 0.0508mL

Explanation: Using the basic formula that states: C acid * V acid = C base * V base. we have:0.568 * 17.88 = 20 * C base.

therefore concentration of the base is 1.0156/20 = 0.0508 mL

7 0
3 years ago
Calculate the solubility of Mg(OH)2 in water at 25 C. You'll find Ksp data in the ALEKS Data tab. Round your answer to significa
elena-s [515]

Answer:

1.12 × 10⁻⁴ M

Explanation:

Step 1: Write the reaction for the solution of Mg(OH)₂

Mg(OH)₂(s) ⇄ Mg²⁺(aq) + 2 OH⁻(aq)

Step 2: Make an ICE chart

We can relate the solubility product constant (Ksp) with the solubility (S) through an ICE chart.

       Mg(OH)₂(s) ⇄ Mg²⁺(aq) + 2 OH⁻(aq)

I                                0                    0

C                              +S                +2S

E                                S                  2S

The solubility product constant is:

Ksp = 5.61 × 10⁻¹² = [Mg²⁺] × [OH⁻]² = S × (2S)² = 4S³

S = 1.12 × 10⁻⁴ M

8 0
3 years ago
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