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OleMash [197]
3 years ago
14

A 1.00 L volume of HCl reacted completely with 2.00 L of 1.50 M Ca(OH)2 according to the balanced chemical equation below. 2HCl

+ Ca(OH)2 mc013-1.jpg CaCl2 + 2H2O What was the molarity of the HCl solution? 0.375 M 1.50 M 3.00 M 6.00 M
Chemistry
2 answers:
jolli1 [7]3 years ago
8 0

The molarity  of the HCl  solution is   6.00M

<em>Calculation</em>

<em> 2HCl + Ca(OH)2→ CaCl2 +2H2O</em>

 Step 1:find the   moles of Ca(OH)2

 =  molarity  x volume

=  2l x 1.5 mol/l =  3 .00 moles


Step 2:use the  mole ratio  of HCl : Ca(OH)2 to calculate the moles of HCl

That is Ca(OH)2 :HCl  is 2:1 therefore the moles of HCl= 3.00 moles x2= 6.00 moles.


step 3: find the molarity of HCl

molarity  of HCl = moles of HCL /  volume  in liters of HCl

   = 6.00 moles/ 1  L = 6.00 M

tensa zangetsu [6.8K]3 years ago
7 0
The answer is D
6.00 M. I just took the test 
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When maganese dioxide is added to hydrogen chloride you get water maganese dichloride and chlorine gas write the balanved equati
babunello [35]

Answer: When maganese dioxide is added to hydrogen chloride you get water maganese dichloride and chlorine gas then balanced equation is MnO_{2} + 4HCl \rightarrow 2H_{2}O + MnCl_{2} + Cl_{2}.

Explanation:

The word equation is given as maganese dioxide is added to hydrogen chloride you get water maganese dichloride and chlorine gas.

Now, in terms of chemical formulae this reaction equation will be as follows.

MnO_{2} + HCl \rightarrow H_{2}O + MnCl_{2} + Cl_{2}

Here, number of atoms on reactant side are as follows.

  • Mn = 1
  • O = 2
  • H = 1
  • Cl = 1

Number of atoms on product side are as follows.

  • Mn = 1
  • O = 1
  • H = 2
  • Cl = 4

To balance this equation, multiply HCl by 4 on reactant side and multiply H_{2}O by 2 on product side. Therefore, the equation can be rewritten as follows.

MnO_{2} + 4HCl \rightarrow 2H_{2}O + MnCl_{2} + Cl_{2}

Hence, number of atoms on reactant side are as follows.

  • Mn = 1
  • O = 2
  • H = 4
  • Cl = 4

Number of atoms on product side are as follows.

  • Mn = 1
  • O = 2
  • H = 4
  • Cl = 4

Since, this equation contains same number of atoms on both reactant and product side. Therefore, this equation is now balanced equation.

Thus, we can conclude that when maganese dioxide is added to hydrogen chloride you get water maganese dichloride and chlorine gas then balanced equation is MnO_{2} + 4HCl \rightarrow 2H_{2}O + MnCl_{2} + Cl_{2}.

6 0
3 years ago
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