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Umnica [9.8K]
3 years ago
15

Calcium hydroxide, Ca(OH)2, is an ionic compound with a solubility product constant, Ksp, of 6.5×10–6. Calculate the solubility

of this compound in pure water.
Chemistry
1 answer:
kari74 [83]3 years ago
5 0

Answer: The solubility of this compound in pure water is 0.012 M

Explanation:

Solubility product is defined as the equilibrium constant in which a solid ionic compound is dissolved to produce its ions in solution. It is represented as K_{sp}

The equation for the ionization of the  is given as:

Ca(OH)_2\rightarrow Ca^{2+}+2OH^-  

By stoichiometry of the reaction:

1 mole of  Ca(OH)_2 gives 1 mole of Ca^{2+} and 2 mole of OH^-

When the solubility of  Ca(OH)_2 is S moles/liter, then the solubility of Ca^{2+}  will be S moles\liter and solubility of OH^- will be 2S moles/liter.

K_{sp}=[Ca^{2+}][OH^{-}]^2

6.5\times 10^{-6}=[S][2S]^2

S=0.012M

Thus solubility of this compound in pure water is 0.012 M

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How much water (H2O ) would form if 4.04 g of hydrogen (H2) reacted with 31.98 g of oxygen (O2 )?
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Answer:

Mass = 36 g

Explanation:

Given data:

Mass of water formed = ?

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Solution:

Chemical equation:

2H₂ + O₂   →   2H₂O

Number of moles of hydrogen:

Number of moles = mass/molar mass

Number of moles = 4.04 g/ 2 g/mol

Number of moles = 2.02 mol

Number of moles of oxygen:

Number of moles = mass/molar mass

Number of moles = 31.98 g/ 32 g/mol

Number of moles = 1.0 mol

Now we will compare the moles of water with hydrogen and oxygen.

                O₂         :         H₂O

                 1           :           2

                H₂         :         H₂O

                 2          :          2

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Number of moles of water formed by oxygen are less thus oxygen will limiting reactant.

Mass of water:

Mass = number of moles × molar mass

Mass = 2 mol × 18 g/mol

Mass = 36 g

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