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gregori [183]
2 years ago
5

Which of the following samples will have the greatest volume at STP?

Chemistry
1 answer:
blsea [12.9K]2 years ago
5 0

Answer:

  • The second choice: <u><em>22 g He </em></u><em>will have the greatest volume at STP</em>

Explanation:

Following Avogadro's principle, under ideal condtions, the <em>volume</em> of the gases at the same conditions of temperature, and pressure, is proportional to the number of molecules.

Then, you can calculate the number of molecules for each of the gases to determine which is the sample with the greatest number of molecules and, hence, which will have the greatest volume at STP (standard temperature and pressure).

The formula to calcualte the number of molecules (in moles) is:

  • n = mass in grams / molar mass

Then, since the mass is the same (22 g) for the four options, the result will be dependent on the molar mass: the gass witht the smallest molar mass will give the largest number of moles for 22 g, and will have the  greatest volume.

<u><em>a) 22 g CO:</em></u>

  • Molar mass of CO ≈ 28 g/mol

<u><em>b) 22 g He:</em></u>

  • Molar mass of He ≈ 4.0 g/mol

<em><u>c) 22 g O₂ </u></em>

  • Molar mass of O₂ ≈ 32 g/mol

<em><u>d) 22 g Cl₂</u></em>

  • Molar mass of Cl₂ ≈ 71 g/mol

<u>Conclusion</u>: since He has the smallest molar mass, the sample of 22 g of He gas will have the greatest volume at STP.

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2 years ago
When 125 grams of FeO react with 25.0 grams of Al, how many grams of Fe can be produced? FeO + Al → Fe + Al2O3 25.9 g Fe 38.7 g
Serga [27]

<u>Answer:</u> The mass of iron produced will be 77.6 grams

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

  • <u>For FeO:</u>

Given mass of FeO = 125 g

Molar mass of FeO = 71.8 g/mol

Putting values in equation 1, we get:

\text{Moles of FeO}=\frac{125g}{71.8g/mol}=1.74mol

  • <u>For aluminium:</u>

Given mass of aluminium = 25.0 g

Molar mass of aluminium = 27 g/mol

Putting values in equation 1, we get:

\text{Moles of aluminium}=\frac{25.0g}{27g/mol}=0.93mol

The given chemical reaction follows:

3FeO+2Al\rightarrow 3Fe+Al_2O_3

By Stoichiometry of the reaction:

2 moles of aluminium metal reacts with 3 mole of FeO

So, 0.93 moles of aluminium metal will react with = \frac{3}{2}\times 0.93=1.395mol of FeO

As, given amount of FeO is more than the required amount. So, it is considered as an excess reagent.

Thus, aluminium metal is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

2 moles of aluminium metal produces 3 mole of iron metal

So, 0.93 moles of aluminium metal will produce = \frac{3}{2}\times 0.93=1.395moles of iron metal

  • Now, calculating the mass of iron metal from equation 1, we get:

Molar mass of iron = 55.85 g/mol

Moles of iron = 1.395 moles

Putting values in equation 1, we get:

1.395mol=\frac{\text{Mass of iron}}{55.85g/mol}\\\\\text{Mass of iron}=(1.395mol\times 55.85g/mol)=77.6g

Hence, the mass of iron produced will be 77.6 grams

4 0
3 years ago
What is the value for AG at 5000 K if AH = -220 kJ/mol and S= -0.05 kJ/(mol-K)?
Serhud [2]

Answer:

C. 30 kJ

Explanation:

Hello there!

In this case, in agreement to the thermodynamic definition of the Gibbs free energy, in terms of enthalpy of entropy:

\Delta G= \Delta H-T\Delta S

It is possible to calculate the required G by plugging in the given entropy and enthalpy as shown below:

\Delta G=-220kJ/mol-5000K*-0.05kJ/mol*K\\\\\Delta G=30kJ/mol

Therefore, the answer is C. 30 kJ .

Best regards!

4 0
2 years ago
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