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gregori [183]
3 years ago
5

Which of the following samples will have the greatest volume at STP?

Chemistry
1 answer:
blsea [12.9K]3 years ago
5 0

Answer:

  • The second choice: <u><em>22 g He </em></u><em>will have the greatest volume at STP</em>

Explanation:

Following Avogadro's principle, under ideal condtions, the <em>volume</em> of the gases at the same conditions of temperature, and pressure, is proportional to the number of molecules.

Then, you can calculate the number of molecules for each of the gases to determine which is the sample with the greatest number of molecules and, hence, which will have the greatest volume at STP (standard temperature and pressure).

The formula to calcualte the number of molecules (in moles) is:

  • n = mass in grams / molar mass

Then, since the mass is the same (22 g) for the four options, the result will be dependent on the molar mass: the gass witht the smallest molar mass will give the largest number of moles for 22 g, and will have the  greatest volume.

<u><em>a) 22 g CO:</em></u>

  • Molar mass of CO ≈ 28 g/mol

<u><em>b) 22 g He:</em></u>

  • Molar mass of He ≈ 4.0 g/mol

<em><u>c) 22 g O₂ </u></em>

  • Molar mass of O₂ ≈ 32 g/mol

<em><u>d) 22 g Cl₂</u></em>

  • Molar mass of Cl₂ ≈ 71 g/mol

<u>Conclusion</u>: since He has the smallest molar mass, the sample of 22 g of He gas will have the greatest volume at STP.

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Answer:

It is an example of double displacement reaction.

4.8 g of NaCl is needed to react.

Explanation:

Balanced reaction: H_{2}SO_{4}(aq.)+2NaCl(s)\rightarrow 2HCl(g)+Na_{2}SO_{4}(aq.)

Here, oxidation states of H, S, O, Na and Cl do not change during reaction. Hence it is not a redox reaction.

In this reaction, cations and anions of the reactants interchange their partners during reaction. Hence, it is an example of double displacement reaction.

As H_{2}SO_{4}(aq.) remain in excess amount therefore NaCl (s) is the limiting reagent. Hence production of HCl entirely depends on amount of NaCl used.

Molar mass of HCl = 36.46 g/mol

So, 3.0 g of HCl = \frac{3.0}{36.46} mol of HCl = 0.082 mol of HCl

According to balanced equation-

2 moles of HCl are produced from 2 moles of NaCl

So, 0.082 moles of HCl are produced from 0.082 moles of NaCl

Molar mass of NaCl = 58.44 g/mol

So, mass of 0.082 moles of NaCl = (0.082\times 58.44) g = 4.8 g

Hence 4.8 g of NaCl is needed to react.

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<h3>Further explanation  </h3>

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<em>(empirical formula) n = molecular formula  </em>

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Moles of Bromine produced = 9 moles

<h3>Further explanation</h3>

Given

9 moles of Chlorine gas

Word equation

Required

Moles of Chlorine produced

Solution

We change the word equation into a chemical equation (with a formula)

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Maybe you mean, <em>how many moles of Bromine can we produce?</em>

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