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Zielflug [23.3K]
3 years ago
9

Draw the structure of the organic product(s) of the grignard reaction between phosgene (clcocl) and excess phenylmagnesium bromi

de, followed by aqueous workup.

Chemistry
2 answers:
Jobisdone [24]3 years ago
8 0
Phosgene on reacting with <span>phenylmagnesium bromide generates benzoyl chloride. 

Since, </span>phenylmagnesium bromide is added in excess. It would further react with benzoyl chloride to form benzophenone.

Benzophenone on further reacting with phenylmagnesium bromide, and aqueous treatment, gives triphenylmethanol. 

Entire reaction pathways is shown below:

Vikentia [17]3 years ago
4 0
<span>This is a three step reaction.
 
Step 1:
           In first step when Phenyl Magnesium Bromide (Grignard Reagent) is treated with phosgene it produces Benzoyl Chloride. In this step Grignard reagent act as a nucleophile while phosgene acts as electrophile.

Step 2:
           The Benzoyl chloride formed in first step still has an electrophillic carbon, therefore, another grignard reagent (which is present in excess) is added to the carbonyl group and results in the elimination of chloride ion (good leaving group) and formation of Benzophenone.

Step 3:
           The benzophenone (ketone) formed in second step contains a carbonyl group with electrophilic carbon. Hence, the grignard reagent is added through nucleophilic addition reaction and forms a tetrahedral intermediate, which upon hydrolysis yields triphenylmethanol (tertiary alcohol). This tertiary alcohol formed can not undergo reaction with grignard reacgent because it does not contain any electrophilic center.</span>
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Construct a three-step synthesis of trans-2-pentene from acetylene by dragging the appropriate formulas into the bins. Note that
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Answer:

The three-step synthesis of trans-2-pentene from acetylene is as follows.

<u>Step -1:</u> Formation of higher order terminal alkyne on reaction with sodium acetylides with haloalkanes.

<u>Step -2:</u> Formation terminal alkyne to nonterminal alkynes.

<u>Step -3:</u> Formation of trans-pent - 2-pent-ene by reduction.

Explanation:

Synthesis of trans-pent-2-yne from ethyne takes place is mainly a three step synthesis which involves formation of higher order terminal alkyne on reaction with sodium acetylides with haloalkane. Second step involves the further alkylation of terminal alkynes to higher order nonterminal alkynes and the third step involves the formation of trans-2-ene by dissolving reduction method.

The chemical reaction of each step of chemical reactions is as follows.

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Natasha2012 [34]

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Which of the following is ignored when determining the relative mass of atoms? (2 points)
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Enter your answer in the provided box. Find the pH of a buffer that consists of 0.34 M HBrO and 0.89 M KBrO (PK, of HBrO = 8.64)
11111nata11111 [884]

Answer : The  pH of buffer is 9.06.

Explanation : Given,

pK_a=8.64

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Concentration of KBrO = 0.89 M

Now we have to calculate the pH of buffer.

Using Henderson Hesselbach equation :

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