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Papessa [141]
4 years ago
8

Subtract p - q from 2p - q + 4. answer the following with explanation

Mathematics
2 answers:
andrey2020 [161]4 years ago
7 0

Answer:

\boxed{p+4}

Step-by-step explanation:

It will be like

=> (2p - q + 4) - (p-q)

=> 2p-q+4-p+q

Combining like terms

=> 2p-p-q+q+4

=> p+4

ra1l [238]4 years ago
5 0

Answer:

Step-by-step explanation:

2p - q + 4 - ( p - q )

2p - q + 4 - p + q

By rearranging the terms

2p - p + 4

( you might think where -q and +q went ???

They are cancelled because they have opposite signs )

∴The answer is p + 4

Hope it helps

plz mark as brainliest!!!!!!!

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Step-by-step explanation:

Answer 1 put all like terms then solve

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Give three examples of how percents are used in the real world????
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When you go to stores and it advertises 25% off or something like that is a big one. tipping 15% or 20% is another application. a third would maybe be the interest you earn on a bank account??
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Parameter or statistic??
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The answer is b hope this helps
6 0
4 years ago
Part A
kap26 [50]

Reflecting the polygon FGHI across the line involves flipping the line across the line y = -1

<h3>How to reflect the polygon?</h3>

The coordinates are given as:

F(2, – 1), G(5,2), H(8, 3), and I(6, 0)

The line of reflection is given as:

y = -1

To reflect the line, we apply the following rule of reflection

(x,y) \to  (x,-y-2)

So, we have the following coordinates of the image

F' = (2, – 1)

G' = (5,-4)

H' = (8, -5)

I' = (6, -2)

See attachment for the image of the reflected polygon

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brainly.com/question/4289712

4 0
2 years ago
A random sample of 100 automobile owners in thestate of Virginia shows that an automobile is driven onaverage 23,500 kilometers
Anastaziya [24]

Answer:

a) 22497.7 < μ< 24502.3

b)  With 99% confidence the possible error will not exceed 1002.3

Step-by-step explanation:

Given that:

Mean (μ) = 23500 kilometers per year

Standard deviation (σ) = 3900 kilometers

Confidence level (c) = 99% = 0.99

number of samples (n) = 100

a) α = 1 - c = 1 - 0.99 = 0.01

\frac{\alpha }{2} =\frac{0.01}{2}=0.005\\ z_{\frac{\alpha }{2}}=z_{0.005}=2.57

Using normal distribution table, z_{0.005 is the z value of 1 - 0.005 = 0.995 of the area to the right which is 2.57.

The margin of error (e) is given as:

e= z_{0.005}\frac{\sigma}{\sqrt{n} }  = 2.57*\frac{3900}{\sqrt{100} } =1002.3

The 99% confidence interval = (μ - e, μ + e) = (23500 - 1002.3, 23500 + 1002.3) =  (22497.7, 24502.3)

Confidence interval = 22497.7 < μ< 24502.3

b) With 99% confidence the possible error will not exceed 1002.3

5 0
4 years ago
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