Answer:
Explanation:
a) 1.00 - 0.12 = 0.88
m = 1200(0.88)^t
b) t = ln(m/1200) / ln(0.88)
c) m = 1200(0.88)^10 = 334.20 g
d) t = ln(10/1200) / ln(0.88) = 37.451... = 37 s
e) t = ln(1/1200) / ln(0.88) = 55.463... = 55 s
Answer:
ACCELERATING OR DECELERATING
Explanation:
I'M NOT SURE
Answer:
B) electrons
Explanation:
When charge is transferred by friction, induction or conduction, the charge carriers are the electrons.
In fact, protons and neutrons are found within the nucleus of the atoms, so they are tightly bound and they cannot be easily gained/given off. On the contrary, electrons are found in the electron clouds around the nucleus, so atoms can more easily gain/lose electrons, which become free and can be passed by an object to another.
The three methods of charging are:
- Friction: by rubbing two objects together, electrons may be transferred from one to another
- Induction: by moving a charged object closer to a neutral object, opposite charges in the neutral object migrate towards the opposite ends of the object, and if the object is connected to the ground, the charges of one polarity leave the object, leaving the object charged
- Conduction: by putting a charged object in contact with a neutral object, electrons can be transferred from the charged object to the neutral one
Answer:
398.0 N = 89.74 pound force
Explanation:
Gravitational force:
R = 6371 km (Radius of the Earth)
At the surface, weight of the surface w =220 pounds = 978.61 N
2250 miles = 3621024 m
total distance from the center of the Earth
3621024 m + 6.371×10⁶ m = 9.99×10⁶ m
398.0 N = 89.74 pound force
Answer:
the magnitude of a uniform electric field that will stop these protons in a distance of 2 m is 10143.57 V/m or 1.01 × 10⁴ V/m
Explanation:
Given the data in the question;
Kinetic energy of each proton that makes up the beam = 3.25 × 10⁻¹⁵ J
Mass of proton = 1.673 × 10⁻²⁷ kg
Charge of proton = 1.602 × 10⁻¹⁹ C
distance d = 2 m
we know that
Kinetic Energy = Charge of proton × Potential difference ΔV
so
Potential difference ΔV = Kinetic Energy / Charge of proton
we substitute
Potential difference ΔV = ( 3.25 × 10⁻¹⁵ ) / ( 1.602 × 10⁻¹⁹ )
Potential difference ΔV = 20287.14 V
Now, the magnitude of a uniform electric field that will stop these protons in a distance of 2 m will be;
E = Potential difference ΔV / distance d
we substitute
E = 20287.14 V / 2 m
E = 10143.57 V/m or 1.01 × 10⁴ V/m
Therefore, the magnitude of a uniform electric field that will stop these protons in a distance of 2 m is 10143.57 V/m or 1.01 × 10⁴ V/m