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elena-s [515]
3 years ago
13

A highly volatile substance has an initial mass of 1200 g and its mass is reduced by 12% each second.

Physics
1 answer:
Softa [21]3 years ago
4 0

Answer:

Explanation:

a) 1.00 - 0.12 = 0.88

m = 1200(0.88)^t

b) t = ln(m/1200) / ln(0.88)

c) m = 1200(0.88)^10 = 334.20 g

d) t = ln(10/1200) / ln(0.88) = 37.451... = 37 s

e) t = ln(1/1200) / ln(0.88) = 55.463... = 55 s

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