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Lemur [1.5K]
3 years ago
7

Which planet do most known extrasolar planets most resemble?

Physics
2 answers:
Anuta_ua [19.1K]3 years ago
4 0

Answer:

planet Jupiter

Explanation:

Most of the extrasolar planets that have been discovered are most like the planet Jupiter in our solar system

Serjik [45]3 years ago
3 0

Answer:

the correct answer is jupiter

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PSYCHOLOGY<br><br> All of our behaviors have been learned.<br> OA True<br> OB False
Mekhanik [1.2K]

Answer:

A True

the answer is true

6 0
2 years ago
TRUE OR FALSE<br> Culture creates the context for behavior in society.
densk [106]
The answer is true


Hope its help;)
7 0
3 years ago
Read 2 more answers
A cement block accidentally falls from rest from the ledge of a 52.9-m-high building. When the block is 14.3 m above the ground,
Anna007 [38]

Answer:

The man has at most 0.418 secs to get out of the way

Explanation:

To determine how much time at most the man has to get out of the way, we will calculate the time it will take the block to reach height 1.94m from height 14.3m.

To do this, we will first determine the time it will take the block to reach height 1.94 m from height 52.9 m and find the time it takes the block to reach height 14.3m above the ground from the same height (52.9 m), the difference is the time the man has to get out of the way.

Now, the time it will take the block to reach height 1.94 m from height 52.9 m

This means the time it will take the block to travel a height distance of 52.9m - 1.94m = 50.96m

From one of the equations of motions for free falling bodies

h = ut + 1/2(gt²)

Where h is the height

u is the initial velocity

t is the time

and g is the acceleration due to gravity (Take g = 9.8 m/s²)

From the question, the block falls from rest

∴ u = 0 m/s

h = 50.96 m

Putting these into the equation

50.96 = 0(t) + 1/2(9.8)(t²)

50.96 = 4.9t²

t² = 50.96/4.9

t² = 10.4

t = √10.4

t = 3.225 secs

This is the time it will take to reach height 1.94m (that is to reach the man)

For the time it takes the block to reach height 14.3m above the ground from height 52.9 m

That is, the time it takes the block to travel a height distance of 52.9m - 14.3m = 38.6 m

Here,

h = 38.6 m

and u = 0 m/s

Putting these into the same equation

h = ut + 1/2(gt²)

38.6 = 0(t) + 1/2(9.8)(t²)

38.6 = 4.9t²

t² = 38.6/4.9

t² = 7.878

t = √7.878

t = 2.807 secs

This is the time it takes the block to reach height 14.3 m

Now, the difference in time is 3.225secs - 2.807 secs = 0.418 secs

Hence, the man has at most 0.418 secs to get out of the way.

7 0
3 years ago
1.a machine gun fires a ball with an initial velocity of 600m/s with an elevation of 30° with respect to the ground neglecting a
Sedbober [7]

Answer:

See explanation

Explanation:

a) maximum height of a projectile = u sin^2θ/2g

H= 600 × (sin 30)^2/2 × 10

H= 7.5 m

b) Time of flight

t= 2u sinθ/g

t= 2 × 600 sin 30/10

t= 60 seconds

Range

R= u^2sin2θ/g

R= (600)^2 × sin2(30)/10

R= 31.2 m

3 0
2 years ago
What is the kinetic energy of a hammer that starts from rest and decreases its potential energy by 10 kJ?
erma4kov [3.2K]

Answer:

final kinetic energy of the hammer is 10 kJ

Explanation:

As we know that there is no non conservative force on the system

So here we can use the theory of mechanical energy conservation

So we will have

\Delta K + \Delta U = 0

here we know that

\Delta U = - 10 kJ

from above expression now

K_f - K_i - 10 kJ = 0

K_f - 0 = 10 kJ

so final kinetic energy of the hammer is 10 kJ

3 0
3 years ago
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