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pickupchik [31]
3 years ago
15

Which of the following ordered pairs could be placed in the table and still have the relation qualify as a linear function?

Mathematics
2 answers:
vagabundo [1.1K]3 years ago
4 0
Linear functions have to have the same slope between any 2 points

find the slope betwen them
slope betwen 2 points (x1,y1) and (x2,y2) is
(y1-y1)/(x2-x1)
given
(1,12) and (3,9)
slope=(9-12)/(3-1)=-3/2

if we wanted to chek furthere, we check (3,9) and (5,6) and fnd that the slope is also -3/2

so
y=mx+b
m=slope
b=yint
y=-3/2x+b
find b
if x=1 then y=12
12=-3/2+b
add 3/2 both sides
12+3/2=b
13+1/2=b
26/2+1/2=b
27/2=b
y=-3/2x+27/2
try them

we have 2 x values
7 and 3
input them and see their outputs

for x=7
y=-3/2(7)+27/2
y=-21/2+27/2
y=6/2
y=3
(7,3) is a valid point

for x=3
hold a second, we already have a x=3
it is (3,9)
none of them


answer is (7,3)
EleoNora [17]3 years ago
3 0

Answer:

Your answer would be A (7,3)

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Leni [432]

Answer:

x^3+5x^2+3x

Step-by-step explanation:

1) divide each term in the numerator by the term in denominator:

(remember when dividing subtract the smaller exponent from larger exponent

for example: \frac{x^a}{x^b} say a is the larger exponent, do x^a^-^b

x^4/x=x^3

5x^3/x=5x^2

3x^2/x=3x

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x^3+5x^2+3x

hope this helps!

6 0
3 years ago
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Karen is planning to drive 2421 miles on a road trip. If she drives 269 miles a day, how many days will it take to complete the
vichka [17]
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Solve the following differential equations or initial value problems. In part (a), leave your answer in implicit form. For parts
shepuryov [24]

Answer:

(a) (y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) y = arctan(t(lnt - 1) + C)

(c) y = -1/ln|0.09(t + 1)²/t|

Step-by-step explanation:

(a) dy/dt = (t^2 + 7)/(y^4 - 4y^3)

Separate the variables

(y^4 - 4y^3)dy = (t^2 + 7)dt

Integrate both sides

(y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) dy/dt = (cos²y)lnt

Separate the variables

dy/cos²y = lnt dt

Integrate both sides

tany = t(lnt - 1) + C

y = arctan(t(lnt - 1) + C)

(c) (t² + t) dy/dt + y² = ty², y(1) = -1

(t² + t) dy/dt = ty² - y²

(t² + t) dy/dt = y²(t - 1)

(t² + t)/(t - 1)dy/dt = y²

Separating the variables

(t - 1)dt/(t² + t) = dy/y²

tdt/(t² + t) - dt/(t² + t) = dy/y²

dt/(t + 1) - dt/(t(t + 1)) = dy/y²

dt/(t + 1) - dt/t + dt/(t + 1) = dy/y²

Integrate both sides

ln(t + 1) - lnt + ln(t + 1) + lnC = -1/y

2ln(t + 1) - lnt + lnC = -1/y

ln|C(t + 1)²/t| = -1/y

y = -1/ln|C(t + 1)²/t|

Apply y(1) = -1

-1 = ln|C(1 + 1)²/1|

-1 = ln(4C)

4C = e^(-1)

C = (1/4)e^(-1) ≈ 0.09

y = -1/ln|0.09(t + 1)²/t|

8 0
4 years ago
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PIT_PIT [208]

You would pay $5.54 on that item.

Step-by-step explanation:

Given,

Cost of item = $63

Sales tax rate = 8.8%

Amount of sales tax = 8.8% of cost of item

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Amount of sales tax = $5.54

You would pay $5.54 on that item.

Keywords: percentage, division

Learn more about percentages at:

  • brainly.com/question/1836777
  • brainly.com/question/2115122

#LearnwithBrainly

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