Which of the following ordered pairs could be placed in the table and still have the relation qualify as a linear function?

2 answers:

4 0

Linear functions have to have the same slope between any 2 points

find the slope betwen them
slope betwen 2 points (x1,y1) and (x2,y2) is
(y1-y1)/(x2-x1)
given
(1,12) and (3,9)
slope=(9-12)/(3-1)=-3/2

if we wanted to chek furthere, we check (3,9) and (5,6) and fnd that the slope is also -3/2

so
y=mx+b
m=slope
b=yint
y=-3/2x+b
find b
if x=1 then y=12
12=-3/2+b
add 3/2 both sides
12+3/2=b
13+1/2=b
26/2+1/2=b
27/2=b
y=-3/2x+27/2
try them

we have 2 x values
7 and 3
input them and see their outputs

for x=7
y=-3/2(7)+27/2
y=-21/2+27/2
y=6/2
y=3
(7,3) is a valid point

for x=3
hold a second, we already have a x=3
it is (3,9)
none of them

answer is (7,3)

EleoNora [17]3 years ago

3 0

Answer:

Your answer would be A (7,3)

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What is the distance between (-3,2) and (3,0)

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Answer:

right 6 and down 2

Step-by-step explanation:

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4 0

3 years ago

Either use technology to find the P-value or use

Akimi4 [234]

Answer:

The first step is calculate the degrees of freedom, on this case:

$df=n-1=21-1=20$

Since is a one side left tailed test the p value would be:

$p_v =P(t_{(20)}$

And we can use the following excel code to find it: "=T.DIST(-0.024,20,TRUE)"

Step-by-step explanation:

Data given and notation

$\bar X$ represent the mean

$s$ represent the sample standard deviation

$n=21$ sample size

$\mu_o =140$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t=-0.024 would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean for the widths of tornadoes is lower than 140 yd, the system of hypothesis would be:

Null hypothesis: $\mu \geq 140$

Alternative hypothesis: $\mu < 140$

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

The statistic is given by: $t = -0.024$