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krek1111 [17]
3 years ago
13

How to express this to a single logarithm

Mathematics
1 answer:
Alona [7]3 years ago
6 0
9logbase6zxy

Rules of logs is that when you add logarithms together you’re really multiplying.

Hope this helps!
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What would be the critical value for a two-tailed, one-sample t test with 26 degrees of freedom (df = 26) and an alpha level (p
Alika [10]

Answer: The critical value for a two-tailed t-test = 2.056

The critical value for a one-tailed t-test = 1.706

Step-by-step explanation:

Given : Degree of freedom : df= 26

Significance level : \alpha=0.05

Using student's t distribution table , the critical value for a two-tailed t-test will be :-

t_{\alpha/2, df}=t_{0.025,26}=2.056

The critical value for a two-tailed t-test = 2.056

Again, Using student's t distribution table , the critical value for a one-tailed t-test will be :-

t_{\alpha, df}=t_{0.05,26}=1.706

The critical value for a one-tailed t-test = 1.706

6 0
3 years ago
How do you simplify 4/20
Anna71 [15]
\sf \frac{4}{20}~\underrightarrow{\sf ~simplify~by~4~~}~\frac{4:4}{20:4} =\boxed{\sf  \frac{1}{5} }
3 0
3 years ago
Read 2 more answers
If two cards are drawn without replacement from an ordinary​ deck, find the probability of and a being drawn.
Ivan

Answer:

4/52

Step-by-step explanation:

4 0
3 years ago
Tickets for a dance recital cost $15 for adults and $7 for children. The dance company sold 253 tickets, and the total receipts
elixir [45]

Answer:

Adult tickets =125

Child tickets = 128

Step-by-step explanation:

Let the number of adult and children tickets sold be x and y respectively

So that

x+y= 253--------1

Since total sales/receipt is $2,771

And given that tickets for a dance recital cost $15 for adults and $7 for children hence

15x+7y= 2771-------2

Solving equation 1 and 2 simultaneously we have

x+y= 253---------------1

15x+7y= 2771----------2

Let us multiply equation 1 by 15 to get equation 3 to eliminate x and subtract equation 2 from 3

15x+15y=3795---------3

-{15x+7y= 2771----------2

0+8y=1024

8y= 1024

y= 1024/8

y= 128 tickets

So solve for x let us put y= 128 in equation 1

x+ 128=253

x=253-128

x= 125 tickets

8 0
2 years ago
Approximately 12.6% of all (untreated) Jonathan apples had bitter pit in a study conducted by the botanists Ratkowsky and Martin
bagirrra123 [75]

Answer:

Step-by-step explanation:

Let n be a random variable that represents the first Jonathan apple chosen at random that has bitter pit.

a) P(X = n) = q(n-1)p, where q = 1 - p.

From the information given, probability if success, p = 12.6/100 = 0.126

b) for n = 3, the probability value from the geometric probability distribution calculator is

P(n = 3) = 0.096

For n = 5, the probability value from the geometric probability distribution calculator is

P(n = 5) = 0.074

For n = 12, the probability value from the geometric probability distribution calculator is

P(n = 12) = 0.8

c) For n ≥ 5, the probability value from the geometric probability distribution calculator is

P(n ≥ 5) = 0.58

d) the expected number of apples that must be examined to find the first one with bitter pit is the mean.

Mean = 1/p

Mean = 1/0.126 = 7.9

Approximately 8 apples

7 0
3 years ago
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