Answer:
HX (aq) + H₂O (l) ⇄ H₃O⁺ (aq) + X⁻ (aq)
Acid Base Conj. acid Conj. base
Explanation:
The equation is:
HX (aq) + H₂O (l) ⇄ H₃O⁺ (aq) + X⁻ (aq)
This is the typical equilibrium for a weak acid. It would complete if we notice the Ka.
HX (aq) + H₂O (l) ⇄ H₃O⁺ (aq) + X⁻ (aq) Ka
1 mol of hypothetic HX acid react to 1 mol of water in order to release a proton and make hydronium and generate the X⁻ anion.
HX will be the acid, in this case a weak one and water will be the base. Water is able to accept a proton to make itslef hydronium
Hydronium is the conjugate acid.
The X⁻ will be the conjugate strong base.
This ion can generate the acid form again, that's why it is strong, because it can make hydrolisis.
X⁻ (aq) + H₂O (l) ⇄ HX (aq) + OH⁻(aq) Kb
In this case, the anion will be the conjugate base which it takes a proton from water (acid form) to make a conjugate acid, the HX and a conjugate base, OH⁻
The number of moles of H atoms in 15.2 grams of pure ice is 0.850 moles
The number of moles of O atoms in 15.2 grams of pure ice is 13.50 moles
<h3>What is an atom?</h3>
An atom is a smallest indivisible particle of a chemical element that is capable of independent existence.
- Pure ice contains the H2O molecules and the molar mass of H2O is 18.02 g/mol
Using the relation:
- number of moles = mass/molar mass
The number of moles of H2O = 15.2 grams/18.02 g/mol
number of moles of H2O = 0.8435 moles
If the atomic mass of H and O are as follow:
- the atomic mass of H atom is = 1.00784 g/mol
- the atomic mass of O atom is = 15.999 g/mol
Then:
the number of H atoms in 15.2 grams of pure ice = mass of H atom × molar mass of H2O.
the number of H atoms = 0.8435 mol × 1.00784 g/mol
the number of H atoms = 0.850 moles
the number of O atoms in 15.2 grams of pure ice = 0.8435 mol × 15.999 g/mol
the number of O atoms = 13.50 moles
Learn more about atoms here:
brainly.com/question/25832904
When iron loses the 2 4s electrons, it attains a valency of +2. Sometimes, iron will also lose one of the paired electrons from 3d orbital, leaving the entire 3d orbital filled with unpaired electrons (which provides a more stable configuration). In this case, its valency will be +3.
