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skelet666 [1.2K]
4 years ago
6

Draw the products of the acid-base reaction between stearic acid and OH-

Chemistry
1 answer:
jok3333 [9.3K]4 years ago
7 0

Answer:

Products are stearate anion and water.

Explanation:

Stearic acid is a 18-carbon chain molecule containing -COOH group. IUPAC name of stearic acid is octadecanoic acid.

Molecular formula of stearic acid is C_{17}H_{35}CO_{2}H.

When OH^{-} is added into stearic acid, OH^{-} removes a proton (H^{+}) from acidic -COOH group and forms stearate anion and water as products.

The balanced acid-base reaction is given as:

                  C_{17}H_{35}CO_{2}H+OH^{-}\rightleftharpoons C_{17}H_{35}CO_{2}^{-}+H_{2}O

Structure of products are given below.

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Según la Organización Mundial de la Salud, el nitrato de plata ( densidad = 4.35 g/cc ) es una sustancia con propiedades cáustic
OlgaM077 [116]

Answer:

737.52 mL de agua

Explanation:

En este caso solo debes usar la expresión de molaridad de una solución la cual es:

M = moles / V

Donde:

V: Volumen de solución.

Como queremos saber la cantidad de agua, queremos saber en otras palabras cual es la cantidad de solvente que se utilizó para preparar los 800 mL de disolución.

Una disolución se prepara con un soluto y solvente. El soluto lo tenemos, que es el nitrato de plata. Con la expresión de arriba, calculamos los moles de soluto, y luego su masa. Posteriormente, calculamos el volumen con la densidad, y finalmente podremos calcular el solvente de esta forma:

V ste = Vsol - Vsto

Primero calcularemos los moles de soluto:

moles = M * V

moles = 2 * 0.800 = 1.6 moles

Con estos moles, se calcula la masa usando el peso molecular reportado que es 169.87 g/mol:

m = moles * PM

m = 1.6 * 169.87 = 271.792 g

Ahora usando el valor de la densidad, calcularemos el volumen de soluto empleado:

d = m/V

V = m/d

V = 271.792 / 4.35

V = 62.48 mL

Finalmente, la cantidad de agua necesaria es:

V agua = 800 - 62.48

V agua = 737.52 mL

8 0
3 years ago
Mass of 2.88x10^-4 mol of ascorbic acid
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Molar mass C₆H₈O₆ = 176.12 g/mol

1 mole ------------------ 176.12 g
2.88x10⁻⁴ mole -------  ?

mass = 2.88x10⁻⁴ * 176.12 / 1

mass ≈ 0.05072 g

hope this helps!
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