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nikitadnepr [17]
3 years ago
8

The reduction of aldehydes, ketones, organic acids and their derivative of the process of alcohols is used for

Chemistry
1 answer:
ikadub [295]3 years ago
8 0

Answer:

Widening of blood vessels.

Explanation:

The reduction of aldehydes, ketones, organic acids causes the formation of alcohols that is used for different process in the human body. This alcohol increase the width of the blood vessels as it enters the bloodstream causing greater flow of blood to the skin surface as well as temporary feeling of warmth. It also increased heat loss and rapid body temperature decrease that produces cooling effect in the body.

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I will make you brainiest! In this analogy, which part of the lunar cycle is waning - from the new moon to the full moon or the
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Answer:

Explanation:

After the glorious appearance of Full Moon, the lunar shape starts to wane, meaning it gets smaller. It's visible later at night and into the early morning, and we see a steadily shrinking shape of the lunar surface that's being lit up.

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3 years ago
Once the following equation is balanced with the smallest set of whole number coefficients, what is the sum of the coefficients?
katrin [286]

Answer:

9

Explanation:

To balance the equation, we need to supply the number of missing coefficients.

There are 2 moles of aluminium on the right hand side, so automatically we need to multiply the number of moles of aluminium by 2 on the left hand side.

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3 years ago
Need help with this question
valentinak56 [21]

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Ground based reflecting telescopes use what part of the
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7 0
2 years ago
Read 2 more answers
2HgO—&gt;2Hg+O2. I start with 46.8 g HgO. What is my theoretical yield of O2?
jok3333 [9.3K]

Answer:

Theoretical yield = 3.52 g

Percent yield =65.34%

Explanation:

Given data:

Mass of HgO = 46.8 g

Theoretical yield of O₂ = ?

Percent yield of O₂ = ?

Actual yield of O₂ =  2.30 g

Solution:

Chemical equation:

2HgO  →   2Hg + O₂

Number of moles of HgO = mass/ molar mass

Number of moles of HgO = 46.8 g / 216.6 g/mol

Number of moles of HgO = 0.22 mol

Now we will compare the moles of HgO with oxygen.

                         HgO             :             O₂

                             2               :               1

                            0.22           :          1/2×0.22 = 0.11 mol

Theoretical yield:

Mass of oxygen = number of moles × molar mass

Mass of oxygen =  0.11 mol × 32 g/mol

Mass of oxygen = 3.52 g

Percent yield :

Percent yield = actual yield / theoretical yield × 100

Percent yield = 2.30 g/ 3.52 g × 100

Percent yield =65.34%

5 0
3 years ago
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