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3 years ago

HELP PLEASE. 50 points!

Chemistry

2 answers:

Lunna [17]3 years ago

4 0

Answer: No e nada sobre ato pero gracias por los puntos

Explanation:

devlian [24]3 years ago

4 0

Answer:

The image is way to small i cant read it

Explanation:

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Plz help me fast!!!!!!!!!!!

Arisa [49]

A) scientific theory

4 0

3 years ago

2 Points

fiasKO [112]

Answer:land

Explanation:

6 0

3 years ago

Why is ice in a glacer considered to be a mineral but water a glacier is not

-Dominant- [34]

If you have a book, read it!! I promise you, it tells you this answer!

5 0

3 years ago

Ethanol (c2h6o) is a common intoxicant and fuel produced from the fermentation of various grains. how many moles of ethanol are

Lynna [10]

n = m / M

Where, n is moles of the compound (mol), m is the mass of the compound (g) and M is the molar mass of the compound (g/mol)

Here, the given ethanol mass = 50.0 kg = 50.0 x 10³ g

Molar mass of the ethanol = (12 x 2 + 1x 6 + 1 x 16) g/mol
= 46 g/mol

Hence, moles in 50.0kg of ethanol = 50.0 x 10³ g / 46 g/mol
= 1086.96 mol

3 0

3 years ago

When a lead acid car battery is recharged by the alternator, it acts essentially as an electrolytic cell in which solid lead(II)

lesya692 [45]

Answer: The mass of lead deposited on the cathode of the battery is 1.523 g.

Explanation:

Given: Current = 62.0 A

Time = 23.0 sec

Formula used to calculate charge is as follows.

$Q = I \times t$

where,

Q = charge

I = current

t = time

Substitute the values into above formula as follows.

$Q = I \times t\\= 62.0 A \times 23.0 sec\\= 1426 C$

It is known that 1 mole of a substance tends to deposit a charge of 96500 C. Therefore, number of moles obtained by 1426 C of charge is as follows.

$Moles = \frac{1426 C}{96500 C/mol}\\= 0.0147 mol$

The oxidation state of Pb in $PbSO_{4}$ is 2. So, moles deposited by Pb is as follows.

$Moles of Pb = \frac{0.0147}{2}\\= 0.00735 mol$

It is known that molar mass of lead (Pb) is 207.2 g/mol. Now, mass of lead is calculated as follows.

$No. of moles = \frac{mass}{molar mass}\\ 0.00735 = \frac{mass}{207.2 g/mol}\\mass = 1.523 g$

Thus, we can conclude that the mass of lead deposited on the cathode of the battery is 1.523 g.

3 0

2 years ago