The noble gas notation of an element includes a noble gas as a condensed way to describe the electronic configuration of an element. IN this case, the nearest noble gas is xenon with an atomic number of 54. Hg's atomic number is 80 so we need 26 more. In this case, after [Xe], the configuration starts with 6s². Hence to complete the configuration the answer is [Xe] 6s2 4f14 5d10
Answer : The incorrect statements are:
(A) When two nonmetals react, the compound formed is ionic.
(B) Two nonmetals can undergo an oxidation-reduction reaction.
Explanation :
Covalent compound : It is defined as the compound which is formed by the sharing of electrons between the atoms forming a compound.
The covalent compound are usually formed when two non-metals react.
The two nonmetals can not undergo an oxidation-reduction reaction.
Ionic compound : It is defined as the compound which is formed when electron gets transferred from one atom to another atom.
Ionic compound are usually formed when a metal reacts with a non-metal.
The metal-nonmetal reaction can always be assumed to be an oxidation-reduction reaction.
For example : 
In this reaction, sodium shows oxidation because the oxidation state changes from (0) to (+1) and and chlorine shows reduction because the oxidation state changes from (0) to (-1).
Hence, the incorrect statements are, (A) and (B)
Answer:
The reaction rate is inversely proportional to the reaction time.
Explanation:
- The reaction rate is the change of the concentration of reactants and products with the time.
<em>∵ Reaction rate = - Δ[reactants]/Δt = Δ[products]/Δt.</em>
<em>∴ The reaction rate is inversely proportional to the time, as the reaction rate increases it will take a lower time.</em>
Answer:
We will have 7.30 grams lead(II) oxide
Explanation:
Step 1: Data given
Mass of lead (II)carbonate = 8.75 grams
Molar mass PbCO3 = 267.21 g/mol
Step 2: The balanced equation
PbCO3 (s) ⇆ PbO(s) + CO2(g)
Step 3: Calculate moles PbCO3
Moles PbCO3 = mass / molar mass
Moles PbCO3 = 8.75 grams / 267.21 g/mol
Moles PbCO3 = 0.0327 moles
Step 4: Calculate moles PbO
For 1 mol PbCO3 we'll have 1 mol PbO and 1 mol CO2
For 0.0327 moles PbCO3 we'll have 0.0327 moles PbO
Step 5: Calculate mass PbO
Mass PbO = moles PbO * molar mass PbO
Mass PbO = 0.0327 moles * 223.2 g/mol
Mass PbO = 7.30 grams
We will have 7.30 grams lead(II) oxide
Answer:1-methoxy-2,4-dinitrobenzene
Explanation:
The nitro groups are strongly electron withdrawing and promote nucleophilic substitution reactions where one of the original substituents is removed and replaced by a strong nucleophile such as the methoxy group. The mechanism of the reaction is attached below. The electron withdrawing nitrogroup assists the formation of the intermediate in the reaction as shown.