Plz help me fast!!!!!!!!!!!

An ionic compound is a chemical compound dissociated into positive and negative ions, but globally neutral (it is a bond that us

Firdavs [7]

True

Explanation:

Ionic compounds are chemical compounds that dissociates into positive and negative ions and are globally neutral due to the charge balance. They are made up of metals and non-metals.

Ionic bonds are formed between two kinds of atoms having a large electronegativity difference.
It is usually between metals and non-metals.
The formation of this bond type involves the transfer of electrons from the less electronegative atom such that the two kinds of atoms now have completely filled outer shell like the noble gases.
This transfer makes the metal positively charged while the non-metal becomes negatively charged.
The atoms forms ions that are oppositely charged.
The charges are balanced out leaving a net neutral compound.
The electrostatic force of attraction between these ions is the ionic or electrovalent bond.

learn more:

Ionic compound brainly.com/question/6071838

#learnwithBrainly

6 0

3 years ago

Which lists the elements in order from most conductive to least conductive?

salantis [7]

D is the answer. You're welcome...

7 0

3 years ago

Read 2 more answers

One liter of oxygen gas at standard temperature and pressure has a mass of 1.43 g. The same volume of hydrogen gas under these c

Alchen [17]

Answer:

Indeed, the two samples should contain about the same number of gas particles. However, the molar mass of $\rm O_2\; (g)$ is larger than that of $\rm H_2\; (g)$ (by a factor of about $16$ .) Therefore, the mass of the $\rm O_2\; (g)$ sample is significantly larger than that of the $\rm H_2\; (g)$ sample.

Explanation:

The $\rm O_2\; (g)$ and the $\rm H_2\; (g)$ sample here are under the same pressure and temperature, and have the same volume. Indeed, if both gases are ideal, then by Avogadro's Law, the two samples would contain the same number of gas particles ( $\rm O_2\; (g)$ and $\rm H_2\; (g)$ molecules, respectively.) That is:

$n(\mathrm{O_2}) = n(\mathrm{H}_2)$ .

Note that the mass of a gas $m$ is different from the number of gas particles $n$ in it. In particular, if all particles in this gas have a molar mass of $M$ , then:

$m = n \cdot M$ .

In other words,

$m(\mathrm{O_2}) = n(\mathrm{O_2}) \cdot M(\mathrm{O_2})$ .
$m(\mathrm{H_2}) = n(\mathrm{H_2}) \cdot M(\mathrm{H_2})$ .

The ratio between the mass of the $\rm O_2\; (g)$ and that of the $\rm H_2\; (g)$ sample would be:

$\begin{aligned}& \frac{m(\mathrm{O_2})}{m(\mathrm{H_2})} = \frac{n(\mathrm{O_2})\cdot M(\mathrm{O_2})}{n(\mathrm{H_2})\cdot M(\mathrm{H_2})}\end{aligned}$ .

Since $n(\mathrm{O_2}) = n(\mathrm{H}_2)$ by Avogadro's Law:

$\begin{aligned}& \frac{m(\mathrm{O_2})}{m(\mathrm{H_2})} = \frac{n(\mathrm{O_2})\cdot M(\mathrm{O_2})}{n(\mathrm{H_2})\cdot M(\mathrm{H_2})} = \frac{M(\mathrm{O_2})}{M(\mathrm{H_2})}\end{aligned}$ .

Look up relative atomic mass data on a modern periodic table:

$\rm O$ : $15.999$ .
$\rm H$ : $1.008$ .

Therefore:

$M(\mathrm{O_2}) = 2 \times 15.999 \approx 31.998\; \rm g \cdot mol^{-1}$ .
$M(\mathrm{H_2}) = 2 \times 1.008 \approx 2.016\; \rm g \cdot mol^{-1}$ .

Verify whether $\begin{aligned}& \frac{m(\mathrm{O_2})}{m(\mathrm{H_2})}= \frac{M(\mathrm{O_2})}{M(\mathrm{H_2})}\end{aligned}$ :

Left-hand side: $\displaystyle \frac{m(\mathrm{O_2})}{m(\mathrm{H_2})}= \frac{1.43\; \rm g}{0.089\; \rm g} \approx 16.1$ .
Right-hand side: $\displaystyle \frac{M(\mathrm{O_2})}{M(\mathrm{H_2})}= \frac{31.998\; \rm g \cdot mol^{-1}}{2.016\; \rm g \cdot mol^{-1}} \approx 15.9$ .

Note that the mass of the $\rm H_2\; (g)$ sample comes with only two significant figures. The two sides of this equations would indeed be equal if both values are rounded to two significant figures.

7 0

4 years ago

Why can you predict the base sequence of one strand in a molecule of DNA if you know the sequence of the other strand?

lukranit [14]

C - In DNA, each base pairs up with only
one other base.

Pretty confident on this answers :D

7 0

3 years ago

Can you look at the picture and tell me that answer ? Thank you

zepelin [54]

The answer is choice (1).

In case you're interested in the solution for future reference:

-- Density = (mass) / (volume)

-- The scale shows that the mass of the sample is 60 grams.

-- The graduated cylinder has 24 mL in it <em>without</em> the sample.
The graduated cylinder has 34 mL in it <em>with</em> the sample.
The volume of the sample is (34mL - 24mL) = 10 mL .

-- Density = mass/volume = 60g / 10mL = 6 g/mL

3 0

3 years ago