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Anna007 [38]
3 years ago
12

How many grams of CO2 are in 8 mol of the compound?

Chemistry
1 answer:
Wittaler [7]3 years ago
5 0
If you look at the periodic table, underneath each element it give you the atomic mass, which has the units g/mol.  So CO2 have a molecular mass (MM) of those combined atomic masses.  

The MM for CO2 would be...
12.01 g/mol + 2(16.00 g/mol) = 44.01 g/mol

This can be used as a conversion to change from moles to grams.

8 mol * (44.01 g / 1 mol) = 352.08 g or 6 x 10 to the 2 g for the significant figures (sig figs) at are shown in your problem.  

You may have just typed 8 instead of 8.0 or 8.00 which would change your sig figs.  It is all important to right now all your zeros, since almost all chemistry calculations involve significant figures.

I solved the above equation using dimensional analysis and had to cancel out the units, in case this is your first chemistry class.

I hope I helped!
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3 years ago
In this system, potential and kinetic energy are ________________ proportional.
brilliants [131]

Answer:

This question is incomplete

Explanation:

There are two major forms of energy; these are potential and kinetic energy. Kinetic energy is the energy present in moving options. Examples include mechanical and electrical energy.

The formula for kinetic energy is 1/2mv² where "m" is mass and "v" is velocity.

While potential energy is the energy present in stationary objects that can be put to use in future. Example includes a ball in its resting state. The formula for potential energy is "mgh" where "m" is mass, "g" is acceleration due to gravity and "h" is height

Considering the law of conservation of energy which states that energy can neither be created nor destroyed but can be transformed from one form to another. Looking at the example provided earlier for potential energy, a ball in its resting position (having a potential energy) when kicked will have a kinetic energy (which can be calculated with the formula provided earlier), hence

Total energy = potential energy (P.E) + kinetic energy (K.E)

This formula and the explanation above can be used to answer the completed question.

NOTE: There is no standard relationship between P.E and K.E. They could be directly or indirectly proportional depending on the circumstance.

5 0
3 years ago
Aluminum sulfate, known as cake alum, has a wide range of uses, from dyeing leather and cloth to purifying sewage. In aqueous so
NISA [10]

Answer:

a) The chemical reaction is given as:

6NaOH(aq)+Al_2(SO_4)_3\rightarrow 2Al(OH)_3(s)+3Na_2SO_4(aq)

2.571 grams of aluminum hydroxide is precipitated.

Explanation:

a) The chemical reaction is given as:

6NaOH(aq)+Al_2(SO_4)_3\rightarrow 2Al(OH)_3(s)+3Na_2SO_4(aq)

b)

Moles of NaOH = n

Volume of the NaOH = 185.5 mL = 0.1855 L( 1 mL =0.001 L)

Molarity of the solution = 0.533 M

n=0.533 M\times 0.1855 mL=0.09887 mol

Moles of aluminum = n

15.8 g of aluminum sulfate per liter.

Volume of solution = 627 mL = 0.627 L (1 mL= 0.001 L)

Mass of aluminium sulfate in solution = 15.8 g/L × 0.627 L =9.9066 g

Moles of aluminum sulfate = \frac{9.9066 g}{342 g/mol}=0.02897 mol

Moles of NaOH = 0.09887 mol

According to reaction, 6 moles of NaOH reacts with 1 mole of aluminum sulfate, then 0.09887 moles of NaOH will recat with :

\frac{1}{6}\times 0.09887 mol=0.01648 mol

This means that sodium hydroxide moles are in limiting amount.So, amount of aluminum hydroxide will depend upon moles of sodium hydroxide.

According to reaction, 6 moles of sodium hydroxide gives 2 moles of aluminium hydroxide, then 0.09887 moles of sodium hydroxide will give :

\frac{2}{6}\times 0.09887 mol=0.03296 mol of aluminum hydroxide

Mass of 0.03296 moles of aluminum hydroxide:

0.03296 mol × 78 g/mol = 2.571 g

2.571 grams of aluminum hydroxide is precipitated.

8 0
3 years ago
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