4.90× 10^2 L
I am guessing that the mass of the air is 6.32 × 10^2 <em>g</em>. Then,
Volume = 6.32 × 10^2 g × (1 L/1.29 g) = 4.90× 10^2 L
Answer:
pOH = 0.3
Explanation:
As KOH is a strong base, the molar concentration of OH⁻ is equal to the molar concentration of the solution. That means that in this case:
With that information in mind we can<u> calculate the pOH </u>by using the following formula:
Moles= mass divided by molar mass
Molar mass= 12.01(4) + 1.01(10)
= 58.14g/mol
Moles=14.5g / 58.14g/mol
=0.249
Therefore there are approx 0.249 moles in a 14.5g sample of C4H10
Answer:try to make a good pic please I have ideas about the topic
Answer:
It's the second one down.
Explanation:
Gold
Mass 197
Number of Protons: 79
Number of Neutrons: 197 - 79 = 118
Number of electrons: = number of protons = 97
