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3 years ago

11

Precautions when using a laboratory thermometer

1 answer:

motikmotik3 years ago

3 0

Answer:

It should be kept upright not tilted.

Bulb should be surrounded from all sides by the substance of which the temperature is to be measured.

The bulb should not touch the surface of the container.

Hope this helps

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Classify each salt as acidic, basic, or neutral? -nh4cl -ca(no32

vichka [17]

The pH of salt depends on the component acid and base that comprise them. For example, if the salt is made up of strong acid and weak base then, the salt is acidic. If the salt is formed from strong base and weak acid then, the salt is basic. For this item, NH4Cl is acidic and also Ca(NO3)2 is acidic.

3 0

3 years ago

Use the information below, to write a word equation, then change it into a balanced symbol equation.

Kamila [148]

Answer:

Mg + 2HCl -> MgCl2 + H2

Explanation:

7 0

3 years ago

What is the molar mass of KOH?

Julli [10]

<h3>Answer:</h3>

56.11 g/mol

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Compound] KOH

<u>Step 2: Identify</u>

[PT] Molar Mass of K - 39.10 g/mol

[PT] Molar Mass of O - 16.00 g/mol

[PT] Molar Mass of H - 1.01 g/mol

<u>Step 3: Find</u>

39.10 + 16.00 + 1.01 = 56.11 g/mol

5 0

2 years ago

What is the area of triangle ABC with vertices A(x¹,y¹), B(x²,y²)and C (x³,y³)??????????<br>

AlexFokin [52]

Answer:

$Area = \frac{1}{2}|x_1(y_2 - y_3)+x_2(y_3 - y_1)+x_3(y_1 - y_2)|$

$Area = 2\ units^2$

Explanation:

Given

$A = (x_1,y_1)$

$B = (x_2,y_2)$

$C = (x_3,y_3)$

Required

Determine the area

The area of a triangle is :

$Area = \frac{1}{2}|A_x(B_y - C_y) + B_x(C_y - A_y) + C_x(A_y - B_y)|$

By substituting values for the x and y coordinates of A, B and C;

We have:

$Area = \frac{1}{2}|x_1(y_2 - y_3)+x_2(y_3 - y_1)+x_3(y_1 - y_2)|$

So:

For instance

$A = (0,3)$

$B= (2,1)$

$C = (2,3)$

The area is:

$Area = \frac{1}{2}|0(1-3) + 2(3-3) + 2(3-1)|$

$Area = \frac{1}{2}| 2*0 + 2*2|$

$Area = \frac{1}{2}| 0 + 4|$

$Area = \frac{1}{2}|4|$

$Area = \frac{1}{2} * 4$

$Area = 2\ units^2$

7 0

3 years ago

If 16.5g of c6h14o2 are reacted vwith .499 mol of o2. How many moles of co2 should be produced

Fed [463]

Answer:

moles of carbon dioxide produced are 410.9 mol.

Explanation:

Given data:

Mass of C₆H₁₄O₂ = 16.5 g

Moles of O₂ = 499 mol

Moles of CO₂ = ?

First of all we will write the balance chemical equation.

2C₆H₁₄O₂ + 17O₂ → 14CO₂ + 12H₂O

moles of C₆H₁₄O₂ = mass × molar mass

moles of C₆H₁₄O₂ = 16.5 g × 118 g/mol

moles of C₆H₁₄O₂ = 1947 mol

Now we compare the moles of CO₂ with moles of O₂ and C₆H₁₄O₂ from balance chemical equation.

O₂ : CO₂

17 : 14

499 : 14/17× 499 = 410.9 moles

C₆H₁₄O₂ : CO₂

2 : 14

1947 : 14/2× 1947 = 13629 moles

Oxygen will be limiting reactant so moles of carbon dioxide produced are 410.9 mol.

5 0

3 years ago

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