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3 years ago

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Chemistry

1 answer:

photoshop1234 [79]3 years ago

3 0

Answer:

<h2>yeah ofcourse </h2>

Explanation:

<h2>PLEASE MARK ME BRAINLIEST AND FOLLOW ME LOTS OF LOVE FROM MY HEART'AND SOUL DARLING TEJASWINI SINHA HERE ❤️</h2>

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Some lichen symbionts can survive independently on bare rocks in the absence of any external source of organic matter due to the

sweet-ann [11.9K]

Answer:

Some lichen symbionts can survive independently on bare rocks in the absence of any external source of organic matter due to the ability of the phototrophic partner to fix CO2 from the air, and nitrogen fixation by the cyanobacterial partner.

Explanation:

Lichen are organisms formed from the symbiotic association of a fungus with an organism capable of photosynthesis, be it an algae, a cyanobacterium, or both.

The fungus depends entirely on the photosynthetic organism in its metabolism of carbohydrates, receiving sugars or saccharine alcohols from it. For its part, the algae depends, for its metabolism, on the water and the mineral substances that the fungus provides it, at the same time that it is also protected by it from too high light intensities.

7 0

3 years ago

A chemist must prepare 900.0mL of sodium hydroxide solution with a pH of 13.90 at 25°C. She will do this in three steps: Fill a

Ierofanga [76]

Answer:

28.58 g of NaOH

Explanation:

The question is incomplete. The missing part is:

"Calculate the mass of sodium hydroxide that the chemist must weigh out in the second step"

To do this, we need to know how much of the base we have to weight to prepare this solution.

First we know that is a sodium hydroxide aqueous solution so, this will dissociate in the ions:

NaOH -------> Na⁺ + OH⁻

As NaOH is a strong base, it will dissociate completely in solution, so, starting with the pH we need to calculate the concentration of OH⁻.

This can be done with the following expression:

14 = pH + pOH

and pOH = -log[OH⁻]

So all we have to do is solve for pOH and then, [OH⁻]. To get the pOH:

pOH = 14 - 13.9 = 0.10

[OH⁻] = 10⁽⁻⁰°¹⁰⁾

[OH⁻] = 0.794 M

Now that we have the concentration, let's calculate the moles that needs to be in the 900 mL:

n = M * V

n = 0.794 * 0.9

n = 0.7146 moles

Finally, to get the mass that need to be weighted, we need to molecular mass of NaOH which is 39.997 g/mol so the mass:

m = 39.997 * 0.7146

3 0

4 years ago

What are the primary atoms that make up the scents that we smell?

Scorpion4ik [409]

Answer:

Molecules make scents. Aromatic ones (That is, containing rings of carbon atoms with delocalised electrons). Some unpleasant smells are due to hydrogen and sulphur groups.

Explanation:

3 0

3 years ago

Read 2 more answers

Who's model was titted the atomic theory of matter"? *

alex41 [277]

Answer:

John Dalton

Explanation:

8 0

3 years ago

When calcium carbonate is added to hydrochloric acid, calcium chloride, carbon dioxide, and water are produced. CaCO3 ( s ) + 2

BigorU [14]

Answer:

19.7 g of CaCl₂ are produced in the reaction

Explanation:

In this excersise we need to know the limiting reactant in order to determine the mass produced of a one of the products

The reaction is: CaCO₃ (s) + 2HCl (aq) → CaCl₂(aq) + H₂O (l) + CO₂(g)

First of all we must find the limiting reactant. For that purpose, we convert the mass of reactants to moles

25 g / 100.08 g/mol = 0.249 moles of carbonate

13 g / 36.45 g/mol = 0.357 moles of HCl

We work with the stoichiometry of the reaction:

1 mol of carbonate reacts with 2 moles of hydrochloric

Then, 0.249 moles of carbonate must react with (0.249 . 2) /1 = 0.498 moles of HCl (We do not have enough HCl, so this is the limtiing reactant)

We work with the stoichiometry reactant / product

2 moles of HCl can produce 1 mol of CaCl₂

Therefore 0.357 moles of HCl must produce (0.357 .1) / 2 = 0.178 moles of chloride.

We convert the moles to mass → 0.178 mol . 110.98 g /1mol = 19.7g

5 0

3 years ago

Anyone available to be a learning partner?​

Anyone available to be a learning partner?