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Kazeer [188]
3 years ago
12

Anyone available to be a learning partner?​

Chemistry
1 answer:
photoshop1234 [79]3 years ago
3 0

Answer:

<h2>yeah ofcourse </h2>

Explanation:

<h2><em><u>PLEASE</u></em><em><u> </u></em><em><u>MARK</u></em><em><u> ME</u></em><em><u> BRAINLIEST</u></em><em><u> AND</u></em><em><u> FOLLOW</u></em><em><u> ME</u></em><em><u> LOTS</u></em><em><u> OF</u></em><em><u> LOVE</u></em><em><u> FROM</u></em><em><u> MY</u></em><em><u> HEART'AND</u></em><em><u> SOUL</u></em><em><u> DARLING</u></em><em><u> TEJASWINI</u></em><em><u> SINHA</u></em><em><u> HERE</u></em><em><u> ❤️</u></em></h2>
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<span>362.51 Kelvin ln (p1/p2) =( dH / R) (1/T2 - 1/T1) ln (760 Torr /520Torr) =( 40,700 Joules / 8.314 J molâ’1K-1)(1/T2 - 1/373K) ln (1.4615) =( 4895.35)(1/T2 - 0.002681) 0.37946 = 4895.35/T2 - (0.002681)(4895.35) 0.37946 = 4895.35/T2 - (13.124) 0.37946 + 13.124 = 4895.35/T2 13.5039 = 4895.35/T2 T2 = 4895.35 / 13.5039 T2 = 362.51 answer is 362.51 Kelvin - 273 answer is also 89.5 Celsius</span>
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Answer: it’s b)

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