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AlladinOne [14]
3 years ago
10

Beta particles will: 1. bend toward the North Pole of a magnet. 2 bend toward the South Pole of the magnet 3 not be affected by

either pole of a magnet
Chemistry
2 answers:
Setler79 [48]3 years ago
8 0
Beta particles will bend toward the South Pole of the magnet.

Hope this helped!
dimulka [17.4K]3 years ago
7 0

Answer:

The correct answer is option 3, that is, will not be affected by either pole of a magnet.

Explanation:

Beta particles refer to the electrons that comprise negative charge. The charge is not influenced by magnets, until and unless it is motion. If it is motion, then its electric current encounters with a force away or towards the magnets. In the question it is not mentioned that the beta particles are in motion, thus, we have to presume that they are just lying there, and thus beta particles will not be affected by either of the poles of a magnet.

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Please answer, please answer please answer please answer<br>my last 2 chemistry question. ​
scoundrel [369]

Answer:

1. filtration and evaporation

2. i) water is added to the sand and salt mixture

ii) then the mixture is filtrated and so the sand and the salt water was seperated

iii) the salt water is heated with the help of burner until the water gets evaporated

iv) after the water gets evaporated, the salt is remained in the container

3. observation:

  • on adding water to the mixture, the salt is completely dissolved in the water
  • when filtrated the sand is seperated from the salt water
  • now the salt water when heated with the burner until the evaporation, the water is evaporated
  • the salt is precipitated and remained in the container

4. cautions:

  • while using the burner, we should be cautious with fire
  • the container that is heated should be holded with the help of a cloth to avoid heat
7 0
3 years ago
What phase will you see one week after
slava [35]

Answer:

yes.

Explanation:

Hotel: trivago

6 0
3 years ago
What is the mass of a 5.00 cm^3 piece of copper having a density of 8.96 g/cm^3
erik [133]

Answer:

44.8 g

Explanation:

Density = mass / Volume

Mass = density x Volume = 8.96x 5 = 44.8 g

5 0
3 years ago
In the equation 2KCIO3 → 2KCI + 302, how many moles of oxygen are produced when 12.61 mol of
Zepler [3.9K]

Answer:

A 19

Explanation:

2 mole of KClO3 produces 3 mole of O3

2 : 3

1 : 3/2

12.61 : 3/2 × 12.61

12.61 : 18.9

12.61 mole of KClO3 produces 18.9mole of O2.

7 0
3 years ago
PLEASE HELP I HAVE THIS TEST TOMORROW AM GIVING MORE POINTS THAN I SHOULD
zavuch27 [327]

Answer:

41.11 g of Ca(OH)2.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

CaO + H2O —> Ca(OH)2

Next, we shall determine the masses of CaO and H2O that reacted and the mass of Ca(OH)2 produced from the balanced equation. This can be obtained as follow:

Molar mass of CaO = 40 + 16 = 56 g/mol

Mass of CaO from the balanced equation = 1 × 56 = 56 g

Molar mass of H2O = (2x1) + 16

= 2 + 16

= 18 g/mol

Mass of H2O from the balanced equation = 1 × 18 = 18 g

Molar mass of Ca(OH)2 = 40 + 2(16 + 1)

= 40 + 2(17)

= 40 + 34

= 74 g/mol

Mass of Ca(OH)2 from the balanced equation = 1 × 74 = 74 g

From the balanced equation above,

56 g of CaO reacted with 18 g of H2O to produce 74 g of Ca(OH)2.

Finally, we obtained the mass of calcium hydroxide, Ca(OH)2 produced from the reaction of 33 g of CaO and 10 g of H2O. This can be obtained as follow:

From the question given above, we were told that when 33 g of CaO and 10 g of H2O reacted, 2 g of CaO were remaining. This implies that H2O is the limiting reactant and CaO is the excess reactant.

Thus, we shall use the limiting reactant to determine the mass of calcium hydroxide, Ca(OH)2 produced because it will give the maximum yield as all of it is consumed in the reaction.

The limiting reactant is H2O and the mass of calcium hydroxide, Ca(OH)2 produced can be obtained as follow:

From the balanced equation above,

18 g of H2O reacted to produce 74 g of Ca(OH)2.

Therefore, 10 g of H2O will react to produce = (10 × 74)/18 = 41.11 g of Ca(OH)2.

Therefore, 41.11 g of Ca(OH)2 were obtained from the reaction.

3 0
3 years ago
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