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Mazyrski [523]
3 years ago
14

Which of the following describes the role of water in supporting the chemical reactions that occur within various life forms? It

is used during photosynthesis to capture sunlight. It is critical in the process of cellular respiration. It adheres to the vascular tissue in plants. It allows sunlight to pass through it.
Chemistry
2 answers:
wel3 years ago
4 0

Answer:

The correct option is;

It is used during photosynthesis to capture sunlight

Explanation:

During photosynthesis, light energy from the Sun is converted and stored in sugars as chemical energy. The Sun light energy is used in the formation of complex sugars such as glucose from the combination of water from the ground and carbon dioxide from the atmosphere while oxygen is released as the byproduct. Organisms are then able to obtain energy from the glucose as well as carbon fiber

The chemical equation for the reaction is as follows;

6CO₂     + 12H₂O + light energy → C₂H₁₂O₆  +  6O₂ + 6H₂O

Carbon,     Water,                            GLucose,  Oxygen,   Water

dioxide

RUDIKE [14]3 years ago
3 0

Answer:

It is critical in the process of ceeluar reespiration.

Explanation:

Water is critical in the process of cellular respiration, which is required for us to extract the energy we do from food. It DOES NOT capture sunlight in photosynthesis. In the first stage of photosynthesis, energy from the sun is captured to make glucose molecules, and oxygen from the water molecules is GIVEN OFF AS WASTE in the process.

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Answer:

b option sir sidd dichhi good book goo

6 0
2 years ago
Describe a sigma bond.A) overlap of two f orbitalsB) end to end overlap of p orbitalsC) s orbital overlapping with the side of a
lyudmila [28]

Answer:

B - End to end overlap of p overlap

Explanation:

Sigma bonds (σ bonds) are the strongest type of covalent chemical bondSigma bonds are formed by end-to-end overlapping. Sigma bonds can occur between any kind of atomic orbitals;The combination of overlapping orbitals can be s-s, s-pz or pz-pz.                              

8 0
2 years ago
For the cell constructed from the hydrogen electrode and metal-insoluble salt electrode, B) calculate the mean activity coeffici
Brut [27]

<u>Question:</u>

For the cell constructed from the hydrogen electrode and metal-insoluble salt electrode, B) calculate the mean activity coefficient for 0.124 b HCl solution if E=0.342 V at 298 K

<u>Answer:</u>

The mean activity coefficient for HCl solution is 0.78.

<u>Explanation:</u>

Activity coefficient is defined as the ratio of any chemical activity of any substance with its molar concentration. So in an electrochemical cell, we can write activity coefficient as γ. The equation for determining the mean activity coefficient is

              E=E_{0}-0.0514 \mathrm{V} \ln \gamma

As we know that E_{0} = 0.22 V and E = 0.342 V, the equation will become

             0.342 V+0.0514 V \ln (0.124)=0.22 V-0.0514 V \ln \gamma

             0.342 V-0.222 V=-0.0514 V(\ln \gamma+\ln 0.124)

             0.12 \mathrm{V}=-0.0514 \mathrm{V}(\ln \gamma+\ln 0.124)

             \frac{0.12}{0.0514}=-\ln (0.124 \gamma)

             -2.3346=\ln (0.124 \gamma)

             e^{-2.3346}=0.124 \gamma

             0.0968=0.124 \gamma

             \gamma=\frac{0.0968}{0.124}=0.78

So, the mean activity coefficient is 0.78.

6 0
3 years ago
Suppose you have just added 200.0 ml of a solution containing 0.5000 moles of acetic acid per liter to 100.0 ml of 0.5000 M NaOH
uranmaximum [27]

Answer:

The final pH is 3.80

Explanation:

Step 1: Data given

Volume of acetic acid = 200.0 mL = 0.200 L

Number of moles acetic acid = 0.5000 moles

Volume of NaOH = 100.0 mL = 0.100 L

Molarity of NaOH = 0.500 M

Ka of acetic acid = 1.770 * 10^-5

Step 2: The balanced equation

CH3COOH + NaOH → CH3COONa + H2O

Step 3: Calculate moles

moles = molarity * volume

Moles NaOH = 0.500 M * 0.100 L

Moles NaOH = 0.0500 moles

Step 4: Calculate the limiting reactant

For 1 mol CH3COOH we need 1 mol NaOH to produce 1 mol CH3COONa and 2 moles H2O

NaOH is the limiting reactant. It will completely be consumed (0.0500 moles). CH3COOH is in excess. There will react 0.0500 moles . There will remain 0.500 - 0.0500 = 0.450 moles

There will be produced 0.0500 moles CH3COONa

Step 5: Calculate the total volume

Total volume = 200.0 mL + 100.0 mL = 300.0 mL

Total volume = 0.300 L

Step 6: Calculate molarity

Molarity = moles / volume

[CH3COOH] = 0.450 moles / 0.300 L

[CH3COOH] = 1.5 M

[CH3COONa] = 0.0500 moles / 0.300 L

[CH3COONa]= 0.167 M

Step 7: Calculate pH

pH = pKa + log[A-]/ [HA]

pH = -log(1.77*10^-5) + log (0.167/ 1.5)

pH = 4.75 + log (0.167/1.5)

pH = 3.80

The final pH is 3.80

7 0
3 years ago
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2 years ago
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