Find, explain, and correct the error in the student work below.

A number that multiplies a variable in a term is a _-

Leto [7]

It is called a variable

8 0

3 years ago

Without plotting points, let M=(-2,-1), N=(3,1), M'= (0,2), and N'=(5, 4). Without using the distanceformula, show that segments

kramer

Given:

M=(x1, y1)=(-2,-1),

N=(x2, y2)=(3,1),

M'=(x3, y3)= (0,2),

N'=(x4, y4)=(5, 4).

We can prove MN and M'N' have the same length by proving that the points form the vertices of a parallelogram.

For a parallelogram, opposite sides are equal

If we prove that the quadrilateral MNN'M' forms a parallellogram, then MN and M'N' will be the oppposite sides. So, we can prove that MN=M'N'.

To prove MNN'M' is a parallelogram, we have to first prove that two pairs of opposite sides are parallel,

Slope of MN= Slope of M'N'.

Slope of MM'=NN'.

$\begin{gathered} \text{Slope of MN=}\frac{y2-y1}{x2-x1} \\ =\frac{1-(-1)}{3-(-2)} \\ =\frac{2}{5} \\ \text{Slope of M'N'=}\frac{y4-y3}{x4-x3} \\ =\frac{4-2}{5-0} \\ =\frac{2}{5} \end{gathered}$

Hence, slope of MN=Slope of M'N' and therefore, MN parallel to M'N'

$\begin{gathered} \text{Slope of MM'=}\frac{y3-y1}{x3-x1} \\ =\frac{4-(-1)}{5-(-2)} \\ =\frac{3}{2} \\ \text{Slope of NN'=}\frac{y4-y2}{x4-x2} \\ =\frac{4-1}{5-3} \\ =\frac{3}{2} \end{gathered}$

Hence, slope of MM'=Slope of NN' nd therefore, MM' parallel to NN'.

Since both pairs of opposite sides of MNN'M' are parallel, MM'N'N is a parallelogram.

Since the opposite sides are of equal length in a parallelogram, it is proved that segments MN and M'N' have the same length.

7 0

1 year ago

The normal yearly growth of a plant is 60 inches. The normal growth was ten inches more than twice the amount of last year. What

Usimov [2.4K]

The growth of the plant last year was 25 inches if the normal growth was ten inches more than twice the amount of last year.

<h3>What is linear equation?</h3>

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

The normal yearly growth of a plant is 60 inches.

Let's suppose the growth of the plant last year was x

The normal growth was ten inches more than twice the amount of last year.

From the above statement:

10 + 2x = 60

2x = 50

x = 25 inches

Thus, the growth of the plant last year was 25 inches if the normal growth was ten inches more than twice the amount of last year.

Learn more about the linear equation here:

brainly.com/question/11897796

#SPJ1

4 0

2 years ago

NEED HELP FAST PLEASE!

ratelena [41]

(0, -3)(2, -2)
slope = (-2 + 3)/(2-0) = 1/2

b = -3
equation
y = 1/2x - 3

answer is A
<span>y = 1/2x - 3</span>

3 0

4 years ago

Read 2 more answers

A manager at a local company asked his employees how many times they had given blood in the last year. The results of the survey