All categories

4 years ago

What are the answers choices for these three questions

Mathematics

2 answers:

Korolek [52]4 years ago

7 0

Answer:

Fig.1 20

Fig.2 45

Fig.3 115

Step-by-step explanation:

Fig.1

ABC+CBD=57

CBD+17+CBD=57

=> CBD = 20

Fig.2

By observing only: 2x = 90

Then x = 45

Fig.3

x+x+50=180

=>x=65

=> Angle 4 = Angle 3 = 180-65=115

Anna [14]4 years ago

3 0

Answer:

1) 37

2) 60

3)115

Step-by-step explanation:

You might be interested in

Where should a fourth point be located to form a square?

Rina8888 [55]

The answer is (3,-4) because it machtes up with (-5,-4) and (3,4), so it (3,-4) is correct.

3 0

3 years ago

Read 2 more answers

Make r the subject of the formula <br>v = \pi \: h {}^{2}(r - \frac{h}{3})v=πh2(r−3h) <br>

mel-nik [20]

Answer:

$\boxed{r = \frac{h}{3} + \frac{v}{\pi {h}^{2} } }$

Step-by-step explanation:

$Solve \: for \: r: \\ = > v= \pi {h}^{2}(r - \frac{h}{3} ) \\ \\ v=\pi {h}^{2}(r - \frac{h}{3} )is \: equivalent \: to \: {h}^{2}\pi(r - \frac{h}{3} ) = v: \\ = > {h}^{2}\pi(r - \frac{h}{3} ) = v \\ \\ Divide \: both \: sides \: by \: \pi {h}^{2} : \\ = > r - \frac{h}{3} = \frac{v}{\pi {h}^{2} } \\ \\ Add \: \frac{h}{3} \: to \: both \: sides: \\ = > r = \frac{h}{3} + \frac{v}{\pi {h}^{2} }$

7 0

3 years ago

Please help, i will give brainliest to whos first

Wittaler [7]

Thanks with all of my heart!

ik im not first but have a lovely day! u are really kind! never forget that!

6 0

3 years ago

What is the answer to <br> 7y + 5 + (3 - y)?

Nataliya [291]

Answer with factoring: 2(3y+4)

Answer with simplifying: 6y+8

4 0

3 years ago

Read 2 more answers

Use Gauss-Jordan elimination to solve the following linear system.

marysya [2.9K]

Just put the coefients in to a matrix

1x-6y-3z=4
-2x+0y-3z=-8
-2x+2y-3z=-14

$\left[\begin{array}{ccc}1&-6&-3|4\\-2&0&-3|-8\\-2&2&-3|-14\end{array}\right]$
mulstiply 2nd row by -1 and add to 3rd
$\left[\begin{array}{ccc}1&-6&-3|4\\-2&0&-3|-8\\0&2&0|-6\end{array}\right]$
divde last row by 2
$\left[\begin{array}{ccc}1&-6&-3|4\\-2&0&-3|-8\\0&1&0|-3\end{array}\right]$
multiply 2rd row by 6 and add to top one
$\left[\begin{array}{ccc}1&0&-3|-14\\-2&0&-3|-8\\0&1&0|-3\end{array}\right]$
multiply 1st row by -1 and add to 2nd
$\left[\begin{array}{ccc}1&0&-3|-14\\-3&0&0|6\\0&1&0|-3\end{array}\right]$
divide 2nd row by -3
$\left[\begin{array}{ccc}1&0&-3|-14\\1&0&0|-2\\0&1&0|-3\end{array}\right]$
mulstiply 2nd row by -1 and add to 1st row
$\left[\begin{array}{ccc}0&0&-3|-12\\1&0&0|-2\\0&1&0|-3\end{array}\right]$
divide 1st row by -3
$\left[\begin{array}{ccc}0&0&1|4\\1&0&0|-2\\0&1&0|-3\end{array}\right]$

rerange
$\left[\begin{array}{ccc}1&0&0|-2\\0&1&0|-3\\0&0&1| 4\end{array}\right]$

x=-2
y=-3
z=4
(x,y,z)
(-2,-3,4)

B is answer

7 0

3 years ago