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serg [7]
3 years ago
5

A. Blue light has higher energy than red light. Write 3 - 4 sentences comparing these electromagnetic waves with respect to the

following properties: wavelength, frequency, and speed.
b. When a certain amount of blue light and red light shine on a metal surface, only blue light produces an electric current. Write 3 - 4 sentences describing how an increase in the intensity of each light will affect the amount of current produced. How does quantification help explain these observations?
Physics
2 answers:
frosja888 [35]3 years ago
5 0

PART A)

As we know that energy of light depends on its wavelength and frequency as following formula

E = \frac{hc}{\lambda} = h\nu

now we know that wavelength of blue light is less than the red light so here energy of blue light will be more

also we know that

\nu = \frac{c}{\lambda}

so here if wavelength is smaller for blue light so its frequency will be high and the speed of both light will be same in same medium

PART B)

Since we know that frequency of blue light is more than red light as well as wavelength of blue light is less than the wavelength of blue light so here blue light will have more energy

When blue light and red light strike the metal surface then due to more energy of blue light it will release some loosely bonded electrons from metal surface which will contribute in current.

here if we increase the intensity of light then the number of photons that contain the blue light of certain energy will be more and that will contribute more current

So here quantification help as we know that due to quantization only certain frequency or energy will lead to eject electron so all colours will not give this current

stira [4]3 years ago
4 0

<u>Explanation:</u>

  • <u>For a:</u>

The relationship between energy and frequency is given by Planck's equation, which is:

E=h\nu         ......(1)

where, h = Planck's constant

E = energy of the light

\nu = frequency of light

We also know that:

\nu=\frac{c}{\lambda}

Putting the value of frequency in above equation:

E=\frac{hc}{\lambda}     ......(2)

We are given:

Energy of blue light is higher than Red light.

From relation 1, energy is directly related to frequency of the light. So, higher the energy, higher will be the frequency.

From relation 2, energy is inversely related to wavelength of the light. So, higher the energy, lower will be the wavelength.

Thus, blue light has higher energy, higher frequency and lower wavelength as compared to red light which has lower energy, lower frequency and higher wavelength.

  • <u>For b:</u>

If the frequency of the light is more than the threshold frequency, it would be able to emit electrons and increase in intensity would result in more number of photons and hence, more number of electrons.

Whereas, if the frequency of the light is less than the threshold frequency, it would be not be able to emit electrons and increase in intensity would not result in more number of photons and hence, no electrons will be emitted.

Thus, the frequency and energy of blue light is more than the red light.

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The velocity is dueuueue. 100
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3 years ago
If an object is thrown in an upward direction from the top of a building 160 ft. High at an initial speed of 21.82 mi/h what is
viktelen [127]
To solve this problem we are going to use tow kinematic equations for falling objects.
1. Kinematic equation for final velocity: V_{f}=V_{i}+gt
where
V_{f} is the final velocity 
V_{i} is the initial velocity 
g is the acceleration due to gravity 32 \frac{ft}{s^2}
t is the time 
2. Kinematic equation for distance: d=V_{i}t+ \frac{1}{2} gt^2
where
d is the distance 
V_{i} is the initial velocity 
V_{f} is the final velocity
g is the acceleration due to gravity 32 \frac{ft}{s^2}
t is the time 

First, we are going to convert 21.82 mi/h to ft/s:
21.82 \frac{mi}{h} =31.21 \frac{ft}{s}

Next, we are going to use the first equation to find how long it takes for the rock to reach its maximum height.
We know for our problem that the object is thrown in upward direction, so its velocity at its maximum height (before falling again) will be zero; therefore: V_{f}=0. We also know that it initial speed is 31.21 ft/s, so V_{i}=31.21. Lets replace those values in our formula to find t:
V_{f}=V_{i}+gt
0=31.21+(-32)t
-32t=-31.21
t= \frac{-31.21}{-32}
t=0.98seconds

Next, we are going to use that time in our second kinematic equation to find the distance the object reach at its maximum height:
d=V_{i}t+ \frac{1}{2} gt^2
d=31.21(0.98)+ \frac{1}{2} (-32)(0.98)^2
d=15.22ft 

Now we can add the height of the building and the maximum height of the object:
d=160+15.22=175.22ft

Next, we are going to use that height (distance) in our second kinematic equation one more time to fin how long it takes for the object to fall from its maximum height to the ground:
d=V_{i}t+ \frac{1}{2} gt^2
175.22=31.21t+ \frac{1}{2} (32)t^2
16t^2+31.21t-175.22=0
t=2.47 or t=-4.43
Since time cannot be negative, t=2.47 is the time it takes the object to fall to the ground. 

Finally, we can use that time in our first kinematic equation to find the final speed of the object when it hits the ground:
V_{f}=V_{i}+gt
V_{f}=31.21+(32)(2.47)
V_{f}=110.25 ft/s

We can conclude that the speed of the object when it hits the ground is 110.25 ft/s


5 0
3 years ago
US
erastovalidia [21]

Answer:11.5m

Explanation:

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Force exerted by the bullet = mass * acceleration = 0.013 * 850 = 11.05 Newtons.

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NEED HELP FAST<br><br>Are the circuits in a car parallel or series? <br>how do you know?
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